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PIT_PIT [208]
3 years ago
5

Hi I need help what is 15 divided by 156

Mathematics
1 answer:
marissa [1.9K]3 years ago
6 0

the answer to 156/15=10.4

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Help test I don’t know anything
MrRissso [65]

Answer: f=  5/2x +1

Step-by-step explanation: This is really simple actually, all you have to do is take the equation and since it's "f(-2)" you plug in -2 for your variables. Hope this helps! : )

4 0
4 years ago
PLZ HELP if you dont know just dont answer i will give brainliest if you answer right
marta [7]

Answer:  The answer for 1. is 216

The answer for 2. is 224

The answer for 3. is 90

The answer for 4. is 40

The answer for 5. should be 80

Step-by-step explanation:

6 0
3 years ago
Select the correct answer from each drop-down menu.
Natali5045456 [20]

-------------------------------------------------------------------------------------------------------------

Answer:  \textsf{Option A, 13}

-------------------------------------------------------------------------------------------------------------

Given:  \textsf{Side length = 9 units}

Find:  \textsf{Diagonal length}

Solution:  The diagonal length can be easily determined using an equation which uses the side length of a square multiplied by the square root of 2. All we need to do is plug in the values and simplify the expression.

<u>Plug in the values</u>

  • \textsf{Diagonal = Side length} * \sqrt{2}
  • \textsf{Diagonal = 9 units} * \sqrt{2}

<u>Simplify the expression</u>

  • \textsf{Diagonal = 9 units * 1.4142}
  • \textsf{Diagonal = 12.73 units}

Looking at the answer options that have been provided, the option that best fits our scenario is option A, 13.

4 0
2 years ago
Verify that the Intermediate Value Theorem applies to the indicated interval and find the value of c guaranteed by the theorem.
Molodets [167]

Answer:

See verification below

Step-by-step explanation:

Remember that the Intermediate Value Theorem (IVT) states that if f is a continuous function on [a,b] and f(a)<M<f(b), there exists some c∈[a,b] such that f(c)=M.

Now, to apply the theorem, we have that f(0)=0²+0-1=-1, f(5)=5²+5-1=29, then f(0)=-1<11<29=f(5). Additionally, f is continous since it is a polynomial. Then the IVT applies, and such c exists.

To find, c, solve the quadratic equation f(c)=11. This equation is c²+c-1=11. Rearranging, c²+c-12=0. Factor the expression to get (c+4)(c-3)=0. Then c=-4 or c=3. -4 is not in the interval, then we take c=3. Indeed, f(3)=3²+3-1=9+3-1=11.

5 0
4 years ago
Does anybody know how to do repeating signs on big ideas math, like 67.8 repeating?
gtnhenbr [62]
If it’s 67.8 repeating then just put a bar on top of the .8 .
6 0
3 years ago
Read 2 more answers
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