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Natasha2012 [34]

2 years ago

12

Need help answer asap!!!

2 answers:

kompoz [17]2 years ago

8 0

Answer:

It is b. because if you there are 21 whole squares in this.

Step-by-step explanation:

Genrish500 [490]2 years ago

3 0

I'd say A) about 20ft

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How to solve for 6x+3y=21 3x-7y=2

Nastasia [14]

Hi there!

We can solve this equation by using the systems of equations.

We can do this by subtracting like terms from both equations using substitution.

First, let's find the value of y:

6x + 3y = 21
3y = -6x + 21
y = -2x + 7

Then, we should plug it into one of the equations:

3x - 7y = 2
3x - 7(-2x + 7) = 2
3x + 14x - 49 = 2
17x = 51
x = 3

Now, we solve for y by plugging the value of x into the equation:

3x - 7y = 2
3(3) - 7y = 2
9 - 7y = 2
-7y = -7
7y = 7
y = 1

There's your answers.

Hope this helps!

3 0

2 years ago

A store advertises a sale that all items are

Sergio039 [100]

Step-by-step explanation:

true. 30% of 68 is 20.40 if it was 30 percent off it would be 47.60 and it's is 3.40 more off so it is true that it is 30% or more

7 0

2 years ago

Find Y. <br> Round to the nearest tenth.

Andreas93 [3]

Answer:

y=27.8

Step-by-step explanation:

8^2=17^2+16^2-2(16)(17)cosY
8^2-17^2-16^2/-2(17)(16)=cosY
-481/-544=cosY
0.8842=cosY
Y is about 27.8

6 0

3 years ago

Helpppppppppppp ASAP THANKS

strojnjashka [21]

Answer:

c or d

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Each of six jars contains the same number of candies. Alice moves half of the candies from the first jar to the second jar. Then

tino4ka555 [31]

Answer:

The number of candies in the sixth jar is 42.

Step-by-step explanation:

Assume that there are <em>x</em> number of candies in each of the six jars.

⇒ After Alice moves half of the candies from the first jar to the second jar, the number of candies in the second jar is:

$\text{Number of candies in the 2nd jar}=x+\fracx}{2}=\frac{3}{2}x$

⇒ After Boris moves half of the candies from the second jar to the third jar, the number of candies in the third jar is:

$\text{Number of candies in the 3rd jar}=x+\frac{3x}{4}=\frac{7}{4}x$

⇒ After Clara moves half of the candies from the third jar to the fourth jar, the number of candies in the fourth jar is:

$\text{Number of candies in the 4th jar}=x+\frac{7x}{4}=\frac{15}{8}x$

⇒ After Dara moves half of the candies from the fourth jar to the fifth jar, the number of candies in the fifth jar is:

$\text{Number of candies in the 5th jar}=x+\frac{15x}{16}=\frac{31}{16}x$

⇒ After Ed moves half of the candies from the fifth jar to the sixth jar, the number of candies in the sixth jar is:

$\text{Number of candies in the 6th jar}=x+\frac{31x}{32}=\frac{63}{32}x$

Now, it is provided that at the end, 30 candies are in the fourth jar.

Compute the value of <em>x</em> as follows:

$\text{Number of candies in the 4th jar}=40\\\\\frac{15}{8}x=40\\\\x=\frac{40\times 8}{15}\\\\x=\frac{64}{3}$

Compute the number of candies in the sixth jar as follows:

$\text{Number of candies in the 6th jar}=\frac{63}{32}x\\$

$=\frac{63}{32}\times\frac{64}{3}\\\\=21\times2\\\\=42$

Thus, the number of candies in the sixth jar is 42.

4 0

3 years ago