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gtnhenbr [62]
3 years ago
14

What is the length of QR?

Mathematics
1 answer:
Elena L [17]3 years ago
7 0

Answer:

C

Step-by-step explanation:

Since the triangle is right with hypotenuse QR

Use Pythagoras' identity to solve for QR

The square on the hypotenuse is equal to the sum of the squares on the other two sides, that is

QR² = 8² + (8\sqrt{3} )²

       = 64 + 192

       = 256 ( take the square root of both sides )

QR = \sqrt{256} = 16

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If youknow the diameter of the circle, then
                                                                     Circumference = (π) x (Diameter).

If youknow the radius of the circle, then
                                                                     Circumference = (π/2) x(radius).

If you know the area of the circle, then
                                                                     Circumference= 2 √ (π A) .


8 0
3 years ago
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What is the mean of the data?
dmitriy555 [2]

Answer:

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What is the constant of proportionality shown in the graph?<br><br>a 0<br>b. 1/2<br>c. 1/4<br>d. 4​
Grace [21]

Answer:

The answer is B

1/2=B

The answer is B Hope that Helped!

7 0
3 years ago
Needing some help for my online class thanks
pav-90 [236]

Answer:

y=1/2x+2

Step-by-step explanation:

Know that: y=mx+b

Starting for (0,0) count how many times you go up to the marked line (which is 2)

y=1/2x+2

The [+] 2 is where you would start off at on the graph, with 1/2 being the slope go up one and over two.

7 0
3 years ago
an isosceles triangle has congruent sides of 20cm. the base is 10cm. find the height of the triangle.​
dolphi86 [110]

Answer:

\large\boxed{A_\triangle=25\sqrt{15}\ cm^2}

Step-by-step explanation:

Look at the picture.

The formula of an area of a triangle:

A_\triangle=\dfrac{bh}{2}

<em>b</em><em> - base</em>

<em>h</em><em> - height</em>

<em />

We need a length of a height.

Use the Pythagorean theorem:

leg^2+leg^2=hypotenuse^2

We have:

leg=5,\ leg=h,\ hypotenuse=20

Substitute:

5^2+h^2=20^2

25+h^2=400             <em>subtract 25 from both sides</em>

h^2=375\to h=\sqrt{375}\\\\h=\sqrt{(25)(15)}\\\\h=\sqrt{25}\cdot\sqrt{15}\\\\h=5\sqrt{15}\ cm

Calculate the area:

A_\triangle=\dfrac{(10)(5\sqrt{15})}{2}=\dfrac{50\sqrt{15}}{2}=25\sqrt{15}\ cm^2

8 0
3 years ago
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