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joja [24]
3 years ago
10

What is 10% of $190?

Mathematics
2 answers:
aksik [14]3 years ago
7 0
10% of $190 is 19....
solong [7]3 years ago
3 0
10% of 190

10% = 10/100
of = × (multiplication)

So
10/100 × 190
0.1 × 190
19

Therefore 10% of 190 is 19
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Y^2 − 20x − 6y − 51 = 0
grin007 [14]

answer:

Simplifying Y2 + -20X + -6y + -51 = 0

Reorder the terms: -51 + -20X + Y2 + -6y = 0

Solving -51 + -20X + Y2 + -6y = 0

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '51' to each side of the equation. -51 + -20X + Y2 + 51 + -6y = 0 + 51

Reorder the terms: -51 + 51 + -20X + Y2 + -6y = 0 + 51 Combine like terms: -51 + 51 = 0 0 + -20X + Y2 + -6y = 0 + 51 -20X + Y2 + -6y = 0 + 51

Combine like terms: 0 + 51 = 51 -20X + Y2 + -6y = 51

Add '-1Y2' to each side of the equation. -20X + Y2 + -1Y2 + -6y = 51 + -1Y2

Combine like terms: Y2 + -1Y2 = 0 -20X + 0 + -6y = 51 + -1Y2 -20X + -6y = 51 + -1Y2 Add '6y' to each side of the equation. -20X + -6y + 6y = 51 + -1Y2 + 6y Combine like terms: -6y + 6y = 0 -20X + 0 = 51 + -1Y2 + 6y -20X = 51 + -1Y2 + 6y Divide each side by '-20'. X = -2.55 + 0.05Y2 + -0.3y Simplifying X = -2.55 + 0.05Y2 + -0.3y

7 0
3 years ago
If you don't help ill be ruined.
Umnica [9.8K]
I think it’s b I’m not sure but it’s most likely to be b
8 0
3 years ago
What is (10)2 + (-6)2 ? Please do not find the square root yet.
SVETLANKA909090 [29]
Answer is 8

(10)2= 20
(-6)2= -12
20-12= 8

Hope this helped!
7 0
3 years ago
Read 2 more answers
Help with number 13 please if someone can please
guapka [62]

Answer: X=2   Y=-6

Step-by-step explanation:

6 0
3 years ago
Which are the roots of the quadratic function f(q) = q2 – 125? Select two options.
Assoli18 [71]

Answer:

±11.18

Step-by-step explanation:

the function is:

f(q)=q^2-125

and to find the roots we need to find which values of q makes the function result in zero:

q^2-125=0

solving for q:

q^2=125\\q=\sqrt{125}

A square root has two solutions, one positive and one negative, so the solutions are:

q=±\sqrt{125} ≈ ±11.18

the roots of the quadratic equation are +11.18 and -11.18

3 0
4 years ago
Read 2 more answers
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