Answer:
2.28% probability that a person selected at random will have an IQ of 110 or higher
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the probability that a person selected at random will have an IQ of 110 or higher?
This is 1 subtracted by the pvalue of Z when X = 110. So
has a pvalue of 0.0228
2.28% probability that a person selected at random will have an IQ of 110 or higher
63 + 36...there is a common factor of 9
9(7 + 4) <== this is equivalent
63 + 36...there is a common factor of 3
3(21 + 12)...but this is not an answer choice...but it is equivalent
Answer:
She should leave a total of $78.
Step-by-step explanation:
To find this, we first need to find the tip amount. We can do this by multiplying the total by the tip percentage.
$65 * 20% = $13
Now that we have that, we need to add it to the cost.
$65 + $13 = $78
Got this and not sure but best luck with your studying