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Korolek [52]
3 years ago
10

Differentiate the function. f(x) = ln(25 sin^2(x))

Mathematics
1 answer:
tigry1 [53]3 years ago
8 0
Use the chain rule.
Let u = 25sin²(x), such that dy/dx = dy/du · du/dx

\frac{dy}{dx} = \frac{1}{25sin^{2}(x)} \cdot 50cos(x) \cdot sin(x)
\frac{dy}{dx} = \frac{2cos(x) sin(x)}{sin^{2}(x)}

\frac{dy}{dx} = 2cot(x)
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Find the area, in square units, of ️ABC​
Anna [14]

Answer:

52 square units

Step-by-step explanation:

For this you need the length of CB and the length of DA.

|CB| = √(10²+2²) = 2√26

|DA| = √(10²+2²) = 2√26

area of ABC = base · height / 2 = 2√26 · 2√26 / 2 = 52

7 0
3 years ago
2. A circle has a diameter of 12 m. Find the circumference. Use 3.14 for π. DO NOT WRITE THE UNITS IN YOUR ANSWER
guajiro [1.7K]

Answer:

37.68

Step-by-step explanation:

12*3.14

4 0
3 years ago
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Assume: Triangle CDE is a right triangle and Angle D is a right angle. What is the length of the missing side? A) 26 . B) 25 . C
kramer

Answer:

Length of base DE = 24 units

Step-by-step explanation:

Given:

In given triangle, right angle at D

SO,

Perpendicular of given triangle = 32 unit

Hypotenuse of given triangle = 40 unit

Find:

Length of base DE

Computation:

Using Pythagoras theorem

Base = √Hypotenuse² - Perpendicular²

Length of base DE = √Hypotenuse of given triangle² - Perpendicular of given triangle²

Length of base DE = √40² - 32²

Length of base DE = √1,600 - 1,024

Length of base DE = √576

Length of base DE = 24 units

6 0
3 years ago
Please help.... i cant fail
fenix001 [56]

Answer:

Ask your mom or dad

Step-by-step explanation:

You didn't show all the information so that i an anserc

8 0
3 years ago
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for v= 4i - 5j, find unit vector u in the direction of v, and write your answer as a linear combination of the standard unit vec
umka21 [38]

Answer:

a. u=\frac{4\sqrt{41}i }{41}-\frac{5\sqrt{41}j}{41}

Step-by-step explanation:

The given vector is v= 4i - 5j

The magnitude of this vector is;

|v|=\sqrt{(-4)^2+(-5)^2}

|v|=\sqrt{16+25}

|v|=\sqrt{41}

The unit vector u in the direction of v is;

u=\frac{v}{|v|}

u=\frac{4i - 5j}{\sqrt{41}}

u=\frac{4i }{\sqrt{41}}-\frac{5j}{\sqrt{41}}

We rationalize to get

u=\frac{4\sqrt{41}i }{41}-\frac{5\sqrt{41}j}{41}

4 0
3 years ago
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