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DiKsa [7]
2 years ago
14

Please help and show working out

Mathematics
1 answer:
slavikrds [6]2 years ago
7 0

cb^2 + ab^2 = ca^2  pythagorean theorem

cb^2 +6^2 = 12^2

cb^2 +36 = 144

cb^2 = 108

cb = sqrt (108)

sin D = opp /hyp

sin D =bc/cd

sin 55 = sqrt(108)/cd

cd = sqrt(108)/sin 55

cd=12.687

cd = 12.7  to three significant figures

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The Lewis family and the Perry family each used their sprinklers last summer. The water output rate for the Lewis family's sprin
Rashid [163]

The Lewis family and the Perry family each used their sprinklers last summer. The water output rate for the Lewis family's sprinkler was 15 L per hour. The water output rate for the Perry family's sprinkler was 40 L per hour. The families used their sprinklers for a combined total of 65 hours, resulting in a total water output of 1850 L . How long was each sprinkler used

Answer:

Hours of use of sprinkler by Lewis family is 30 hours.

Hours of use of sprinkler by Perry family is 35 hours.

Step-by-step explanation:

Let W = hours of use by Lewis family

65 - W = hours of use by Perry family

Then;

15W + 40*(65 - W) = 1850

15W + 2600 - 40W = 1850

(15 - 40)W = 1850 - 2600

-25W = −750

W = 750/25 = 30

Therefore;

W = 30

65 - W = 65 - 30 = 35

Hence,

Hours of use by Lewis family is 30 hours.

Hours of use by Perry family is 35 hours.

3 0
3 years ago
Solve the quadratic by quadratic formula below<br><br> x squared-14x=-49
lubasha [3.4K]
X^2-14x+49=0

Factor
(x-7)(x-7)

Check
-7-7=-14
-7*-7=49

Use ZPP
x-7=0
x=7

Final answer: x=7
5 0
3 years ago
Read 2 more answers
The area of the shaded region​
sweet-ann [11.9K]

Answer:

37.7

Step-by-step explanation:

Large circle = \pir² = \pi5² = 78.54

Medium circle = \pi3²= 28.27

Small circle = \pi2²= 12.57

78.54-28.27-12.57 = 37.7

8 0
3 years ago
Find all solutions to
BARSIC [14]

Answer:

x= 0 , \frac{1}{14} , \frac{-1}{12}

Step-by-step explanation:

Given, equation is \sqrt[3]{15x-1} + \sqrt[3]{13x+1} = 4\sqrt[3]{x}. →→→ (1)

Now, by cubing the equation on both sides, we get

( \sqrt[3]{15x-1} + \sqrt[3]{13x+1} )³ = (4\sqrt[3]{x})³

⇒ (15x-1) + (13x+1) + 3×\sqrt[3]{15x-1}×\sqrt[3]{13x+1} (\sqrt[3]{15x-1} + \sqrt[3]{13x+1}) = 64 x.

⇒ 28x + 3×\sqrt[3]{15x-1}×\sqrt[3]{13x+1} (4\sqrt[3]{x}) = 64x.        

(since from (1),  \sqrt[3]{15x-1} + \sqrt[3]{13x+1} = 4\sqrt[3]{x})

⇒ 12× \sqrt[3]{15x-1}×\sqrt[3]{13x+1} (\sqrt[3]{x})= 36x.

⇒ 3x = \sqrt[3]{(15x-1)(13+1)(x)}.

Now, once again cubing on both sides, we get

(3x)³ = (\sqrt[3]{(15x-1)(13+1)(x)})³.

⇒ 27x³ = (15x-1)(13x+1)(x).

⇒ 27x³ = 195x³ + 2x² - x

⇒ 168x³ + 2x² - x = 0

⇒ x(168x² + 2x -1) = 0

⇒ by, solving the equation we get ,

x = 0 ; x = \frac{1}{14} ; x = \frac{-1}{12}

therefore, solution is x= 0 , \frac{1}{14} , \frac{-1}{12}

7 0
3 years ago
Change 2.1 to a mixed number​
Brut [27]

Answer: 2\frac{1}{10}

Step-by-step explanation:

2.1 is the same as 21/10

which will give 2\frac{1}{10}

4 0
2 years ago
Read 2 more answers
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