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BigorU [14]
3 years ago
5

Can someone help me with this angle

Mathematics
1 answer:
Zarrin [17]3 years ago
6 0

Answer:

60 degrees

Step-by-step explanation:

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Hiiiooo!! Can someone please help me ❤️❤️❤️
Alex777 [14]

Answer:

8

Step-by-step explanation:

40 ÷ 5 = 8

56 ÷ 7 = 8

so then just divide 64 by the one we know, which is 8

64 ÷ 8 = 8

5 0
3 years ago
What is the ratio for cos B ?
TiliK225 [7]

Answer:

3/5

Step-by-step explanation:

Cos(B) = adjacent/hypotenuse

Cos(B) = 48/80 = 6/10

Cos(B) = 3/5 or 0.6

7 0
3 years ago
1. 172,900,000 how can u convert this number into scientific notation​
trapecia [35]

Answer:

1.72900000 X 10 to the eighth power

Step-by-step explanation:

6 0
4 years ago
For a given recipe, 24 cups of flour are mixed with 12 cups of sugar. How many cups of sugar should be used if 8 cups of flour a
larisa [96]

Answer:

First, 24 divided by 8 equals 3. this means you divide 12 by 3. you get 4. 4 cups of sugar will be used when 8 cups of flour are used.

7 0
1 year ago
Find the interquartile range of the following data set.
BigorU [14]

The interquartile range of 48, 26, 31, 50, 38, 40, 42, 34, 44, 36, is: D. 10.

<h3>What is the Interquartile Range of a Data Distribution?</h3>

The interquartile range of a data distribution is determined as: upper quartile (Q3) - lower quartile (Q1).

<h3>How to Find the Upper Quartile and Lower Quartile of a Data Distribution?</h3>

The upper quartile of a data distribution is the center of the second half of a data distribution while the lower quartile is the center of the first half of a data distribution.

Given the data, 48, 26, 31, 50, 38, 40, 42, 34, 44, 36:

Order the data set as, 26, 31, 34, 36, 38, 40, 42, 44, 48, 50

The first half of the data is: 26, 31, 34, 36, 38.

The center is 34.

Lower quartile (Q1) = 34.

The second half of the data is: 40, 42, 44, 48, 50. The center is 44.

Upper quartile (Q3) = 44.

Interquartile range = 44 - 34

Interquartile range = 10

Learn more about interquartile range on:

brainly.com/question/4102829

#SPJ1

6 0
2 years ago
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