Question

Solve the system below by substitution.

Answer 1

Answer:

$(-4, -1)$

Step-by-step explanation:

$6x-y=-23$

Add y to both sides:

$6x-y+y=-23+y\\6x=-23+y$

Divide both sides by 6:

$\frac{6x}{6}=-\frac{23}{6}+\frac{y}{6}\\x=\frac{-23+y}{6}$

Substitute this into the second equation given:

$2*\frac{-23+y}{6}+5y=-13$

$\frac{-23+16y}{3}=-13$

Multiply both sides by 3:

$-23+16y=-39$

Add 23 to both sides:

$-23+16y+23=-39+23\\16y=-16$

Divide both sides by 16:

$\frac{16y}{16}=\frac{-16}{16}\\y=-1$

We know that $x=\frac{-23+y}{6}$.

Thus, $x=\frac{-23-1}{6}$

$x=-4$

$(x, y) = (-4, -1)$

Answer 2

Answer:

(-4,-1)

Step-by-step explanation: