The drawing seems to suggest that angles BFA, AFE and EFD span a straight angle, just like angles BFC and CFD
This means that you have

But we know that both BFA and EFD measure 70 degrees, so the equation becomes
![[tex]70+AFE+70=180 \iff AFE + 140 = 180](https://tex.z-dn.net/?f=%20%5Btex%5D70%2BAFE%2B70%3D180%20%5Ciff%20AFE%20%2B%20140%20%3D%20180)
So, if you subtract 140 from both sides, you have

The slope is 4/7
Y= 4/7x + 8/7
Hope this helped :)
Answer:
cos
(
390
)
−
4
cot
(
−
45
)
sin
(
330
)
Step-by-step explanation:
Answers:
Q: What is the most they could weigh together?
A: 0.74 kg
-----
Q: What is the least they could weigh together?
A: 0.62 kg
=================================================
Work Shown:
x = weight of first ball
y = weight of second ball
each ball has a weight range of 0.31 kg to 0.37 kg, so,

add straight down to get

which simplifies to

the two soccer balls have a weight range of 0.62 to 0.74, inclusive of both endpoints.
--------
Without using algebra, you basically just add the smallest the two weights could be (0.31) to itself to get 0.31+0.31 = 0.62 which represents the smallest the two weights combined can be. The same happens with the largest weight of 0.37 to get 0.37+0.37 = 0.74 as the max weight of both objects together.
Answer:

Step-by-step explanation:
Given



Required
Determine P
Since P divides the segment into 3:2, P is calculated using

Where



Substitute these values in the above formula:



