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enot [183]
3 years ago
12

Find the equation for a line passing through the point (2,-4) and (4,-6)​

Mathematics
1 answer:
PIT_PIT [208]3 years ago
8 0

Answer:

y=-1x-2

Step-by-step explanation:

y=mx+b is the easiest way to put the two points into a equation

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Select the correct answer from each drop-down menu. observe the functions below. complete the following sentences to compare the
MrRissso [65]

The answers will be:

  1. (4, 5)
  2. remain constant and increase
  3. g(x) exceeds the value of f(x)

<h3>What is Slope and curve?</h3>

a) The slope of the curve g(x) roughly matches that of f(x) at about x=4. Above that point, the curve g(x) is steeper than f(x), so its average rate of change will exceed that of f(x). An appropriate choice of interval is (4, 5).

b) As x increases, the slope of f(x) remains constant (equal to 4). The slope of g(x) keeps increasing as x increases. An appropriate choice of rate of change descriptors is (remain constant and increase).

c) The curves are not shown in the problem statement for x = 8. The graph below shows that g(x) has already exceeded f(x) by x=7. It remains higher than f(x) for all values of x more than that. We can also evaluate the functions to see which is greater:

 f(8) = 4·8 +3 = 35

 g(8) = (5/3)^8 ≈ 59.54 . . . . this is greater than 35

 g(8) > f(8)

d) Realizing that an exponential function with a base greater than 1 will have increasing slope throughout its domain, it seems reasonable to speculate that it will always eventually exceed any linear function (or any polynomial function, for that matter).

To know more about Slope follow

brainly.com/question/3493733

7 0
2 years ago
Help, I have a time limit for this
salantis [7]

Answer:

I believe that it is the first one.

Step-by-step explanation:

5 0
3 years ago
What are the following of this function y = 4sin (2( x - <img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%5Cpi%20%7D%7B4%7D" id="Te
Andrei [34K]

Answer:

See below...

Step-by-step explanation:

For a function whose formula is in this pattern:

y=A\sin\left(B(x-C)\right)

Amplitude: |A|

Period: \frac{2\pi}{B}

Phase Shift:  C

In this question, A=4,\,B=2,\,C=\frac{3\pi}{4}

Amplitude: 4

Period: \frac{2\pi}{2}=\pi

Phase Shift: \frac{3\pi}{4}

There is no vertical shift, so the midline is the x-axis whose equation is y = 0.

Also, because there is no vertical shift, the maximum is 4 and the minimum is -4.

The graph is attached.

6 0
3 years ago
The diagram shows a track composed with a semicircle on each end. The area of the rectangle is 8,400 square meters. What is the
MrRa [10]

Answer:

468.4 meters

Step-by-step explanation:

Find the width of the rectangle.

The area of a rectangle is A=length*width. Substitute the values of length and area and solve for width.

A=length*width

8,400=140*width

60= width

Use the width of the rectangle to find the circumference of the semicircles. Since each semicircle is half of a​ circle, the perimeter of the two semicircles is equal to the circumference of one circle.

The circumference of a circle is equal to pi​d, where d is the diameter. The diameter of the semicircle is the same as  the width of the rectangle.

​So, the diameter is 60 meters. Substitute the diameter into the formula for the circumference and simplify using 3.14 for pi.

≈188.4

(2 times 140)+ 188.4

​So, the perimeter of the track is 468.4 meters.

7 0
3 years ago
F(x)=2x^2-3x+7 evaluate f(-2)
Vilka [71]

Answer:

Step-by-step explanation:

Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?

Let  p(x)=kpx+dp  and  q(x)=kqx+dq  than

f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7  

p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7  

(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)  

So you want:

−2kpk2q=0  

and

kpkq=−1  

and

2kpd2p−3kpdq+7=0  

Now I amfraid this doesn’t work as  −2kpk2q=0  that either  kp  or  kq  is zero but than their product can’t be anything but  0  not  −1 .

Answer: there are no such linear functions.

6 0
2 years ago
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