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Natali5045456 [20]
3 years ago
13

100 POINTS FOR BRAINLIEST! according to the image, whats the answer? Answer wisely for the full 100

Mathematics
2 answers:
stepan [7]3 years ago
3 0

Answer:

Step-by-step explanation:

1. To find the area of a semicircle the formula is

A=\frac{\pi r^2}{2} \\=\frac{\pi 1^2}{2} \\=6.283m^2

The square

A=a^2=2^2=4m^2\\6.283+4=10.283m^2

2. Triangle

A=\frac{ab}{2} \\=\frac{6*2.5}{2} \\=7.5m^2\\7.5*2=15m^2

Rectangle

A=wl=8*13=104m^2

104-15=89m^2

3.

Semicircle

A=\frac{\pi r^2}{2} \\=\frac{\pi 3^2}{2} \\\\=14.137m^2

Square

A=a^2=6^2=36

36-14.137=21.863m^2

insens350 [35]3 years ago
3 0

Answer:

21.863 m

Step-by-step explanation:

You might be interested in
**50 Points Possible** I NEED URGENT HELP <br>please provide a graph
Elina [12.6K]

Answer:

See below.

Step-by-step explanation:

1)

For Ben's social media post, we are told that it was initially shared to only 2 people. However, each of those shares it with 3 people. In other words, Ben's post triples every day. This means that the rate of growth is 3. Thus, Ben's post as an exponential function is:

f(x)=2(3)^x

The 2 represents the initial amount at day 0, and the 3 represents the rate at which the post grows each day.

2)

Similarly, Carter's post was originally sent to 10 people. However, each of the 10 shares it with two others. Therefore, it doubles each day. Thus, the rate is 2. So, Carter's exponential function is:

f(x)=10(2)^x

The 10 represents the initial amount while the 2 represents the rate.

3)

I've use Desmos to graph the functions. Refer to the picture attached. Red is Amber, blue is Ben, and green is Carter.

4)

To find out the number of shares each student's post will receive on day 3 and day 10, simply plug the numbers into the functions. Therefore:

For Amber:

Day 3:

f(3)=3(4)^3=192

Day 10:

f(10)=3(4)^{10}=3,145,728

For Ben:

Day 3:

f(3)=2(3)^3=54

Day 10:

f(10)=2(3)^{10}=118,098

And for Carter:

Day 3:

f(3)=10(2)^3=80

Day 10:

f(10)=10(2)^{10}=10,240

5)

Amber's new graph of:

f(x)=3(4)^x+45

will be a shifted version of her original graph. The new graph will be shifted upwards by 45 units. However, since the 45 is not affected by the x in any way, the change will be minuscule. For instance, her number of shares on day 10 of the old graph is 3,145,728. Even with the additional 45, it will just be: 3,145,773. With enough days, the additional number becomes trivial.

6)

On the 10th day, Amber's post was shared almost 3 million times, while Ben's was shared "only" 118,098 times and Carter's with 10,240. Undoubtedly, Amber's post was the fastest.

7)

If you want to most shares as possible, choose Amber with fewer friends initially but more shares. This is because the exponential potential of a number even just a bit higher is insane. For instance, 3^10 (Ben's rate at 10th day) is only 59,049 while Amber's rate will be 4^10 which is 1,048,576. Amber's number is almost 18 times higher than Ben's. Even if Ben's initial number was say 1,000 or even 1,000,000, Amber would catch up rather quickly. Therefore, the rate is the quintessential part of an exponential growth function.

5 0
3 years ago
(x+5) (×+5)=49. I need to know what x is, how do I solve this?
Archy [21]
(x+5)^2=49
squaer root both sides
x+5=+/-7
minus 5 both sides
x=-5+/-7
x=-5+7=2
x=-5-7=-12


x=2 or -12

4 0
3 years ago
How is this solved using trig identities (sum/difference)?
GenaCL600 [577]
FIRST PART
We need to find sin α, cos α, and cos β, tan β
α and β is located on third quadrant, sin α, cos α, and sin β, cos β are negative

Determine ratio of ∠α
Use the help of right triangle figure to find the ratio
tan α = 5/12
side in front of the angle/ side adjacent to the angle = 5/12
Draw the figure, see image attached

Using pythagorean theorem, we find the length of the hypotenuse is 13
sin α = side in front of the angle / hypotenuse
sin α = -12/13

cos α = side adjacent to the angle / hypotenuse
cos α = -5/13

Determine ratio of ∠β
sin β = -1/2
sin β = sin 210° (third quadrant)
β = 210°

cos \beta = -\frac{1}{2}  \sqrt{3}

tan \beta= \frac{1}{3}  \sqrt{3}

SECOND PART
Solve the questions
Find sin (α + β)
sin (α + β) = sin α cos β + cos α sin β
sin( \alpha + \beta )=(- \frac{12}{13} )( -\frac{1}{2}  \sqrt{3})+( -\frac{5}{13} )( -\frac{1}{2} )
sin( \alpha + \beta )=(\frac{12}{26}\sqrt{3})+( \frac{5}{26} )
sin( \alpha + \beta )=(\frac{5+12\sqrt{3}}{26})

Find cos (α - β)
cos (α - β) = cos α cos β + sin α sin β
cos( \alpha + \beta )=(- \frac{5}{13} )( -\frac{1}{2} \sqrt{3})+( -\frac{12}{13} )( -\frac{1}{2} )
cos( \alpha + \beta )=(\frac{5}{26} \sqrt{3})+( \frac{12}{26} )
cos( \alpha + \beta )=(\frac{5\sqrt{3}+12}{26} )

Find tan (α - β)
tan( \alpha - \beta )= \frac{ tan \alpha-tan \beta }{1+tan \alpha  tan \beta }
tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3}   }{1+(\frac{5}{12}) ( \frac{1}{2} \sqrt{3})}

Simplify the denominator
tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3}   }{1+(\frac{5\sqrt{3}}{24})}
tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3} }{ \frac{24+5\sqrt{3}}{24} }

Simplify the numerator
tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{6}{12} \sqrt{3} }{ \frac{24+5\sqrt{3}}{24} }
tan( \alpha - \beta )= \frac{ \frac{5-6\sqrt{3}}{12} }{ \frac{24+5\sqrt{3}}{24} }

Simplify the fraction
tan( \alpha - \beta )= (\frac{5-6\sqrt{3}}{12} })({ \frac{24}{24+5\sqrt{3}})
tan( \alpha - \beta )= \frac{10-12\sqrt{3} }{ 24+5\sqrt{3}}

7 0
3 years ago
Help me with number 10 please !!
mel-nik [20]
Um idk if its right but i think 
s would be -3,6
r -5,3 
6 0
3 years ago
How many times does 10 go into 44 with remainder
ankoles [38]

Answer:

Answer: 4 Remainder :4

Step-by-step explanation:

10 | 44 |

10*4 = 40

44-40

4

4 0
3 years ago
Read 2 more answers
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