Given:
A(3,0)
B(1,-2)
C(3,-5)
D(7,-1)
1) reflect across x=-4
essentially calculate the difference between the x=-4 line and Px and "add" it in the other direction to x=-4
A(-4-(3-(-4)),0)=A(-11,0)
B(-4-(1-(-4)),-2)=B(-9,-2)
C(-4-(3-(-4),-5))=C(11,-5)
D(-4-(7-(-4)),-1)=D(-15,-1)
2) translate (x,y)->(x-6,y+8)
A(-3,8)
B(-5,6)
C(-3,3)
D(1,7)
3) clockwise 90° rotation around (0,0), flip the x&y coordinates and then decide the signs they should have based on the quadrant they should be in
A(0,-3)
B(-2,-1)
C(-5,-3)
D(-1,-7)
D) Dilation at (0,0) with scale 2/3, essentially multiply all coordinates with the scale, the simple case of dilation, because the center point is at the origin (0,0)
A((2/3)*3,(2/3)*0)=A(2,0)
B((2/3)*1,(2/3)*-2)=B(2/3,-4/3)
C((2/3)*3,(2/3)*-5)=C(2,-10/3)
D((2/3)*7,(2/3)*-1)=D(14/3,-2/3)
If it is 5ft a minute then it must be 10ft every two minutes
A: -5/18
B:1 and 16/35
C: 7/30
D: 7/8
Answer:
-3
Step-by-step explanation:
y = -3x
This is in slope intercept form
y = mx+b where m is the slope and b is the y intercept
The slope is -3 and the y intercept is 0
Side of the square computer screen = 21 inches
It is important to minutely read the details that are already given in the question. the most important information that is given in the question is that the computer screen ia square. Based on this information the answer to the question can be easily deduced.
Then
Area of the computer screen = (Side)^2
= (21)^2 inches square
= 441 inches^2
So the area of the square computer screen is 441 square inches. i hope the procedure is clear enough for you to understand.
