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iragen [17]
3 years ago
9

(4x + 11)° (5.6 - 10)​

Mathematics
1 answer:
Alex73 [517]3 years ago
6 0
10.6x …………………………………………
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Solve using dividing by 10 strategy. Show your work.
OlgaM077 [116]
There would be 200 seats in each section
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3 years ago
Write each phrase as a mathematical expression.
tresset_1 [31]

Answer: (r+8)/4

Step-by-step explanation:

Not much really to explain...

3 0
2 years ago
I think it's either C or D but I'm not sure plzzz help me !?!?!?!
Dennis_Churaev [7]
Using th epythagorean theorem.

52^2-48^2= x^2

2704-2304= x^2

400=x^2

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Final answer: D
3 0
3 years ago
Let x denote the lifetime of a mcchine component with an exponential distribution. The mean time for the component failure is 25
aliina [53]

Answer:

0.1353 = 13.53% probability that the lifetime exceeds the mean time by more than 1 standard deviations

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

The mean time for the component failure is 2500 hours.

This means that m = \frac{2500}, \mu = \frac{1}{2500} = 0.0004

What is the probability that the lifetime exceeds the mean time by more than 1 standard deviations?

The standard deviation of the exponential distribution is the same as the mean, so this is P(X > 5000).

P(X > x) = e^{-0.0004*5000} = 0.1353

0.1353 = 13.53% probability that the lifetime exceeds the mean time by more than 1 standard deviations

4 0
3 years ago
Which co-ordinates do you plot to draw the graph of x + 2y = 3 ?
pychu [463]
Just subisute values that will work
one easy way is to make one sides equal to only one of the placeholders, like y, and then lug in values in for x exg
x+2y=3
subtract x from both sides
2y=3-x
divideb bith sides by 2
y=-1/2x+3
subsitute valudes for x and get values for y
if x=2 then
y=-1/2(2)+3
y==-1+3
y=2
when x=2, y=2
when y=0 then y=3
3 0
3 years ago
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