Y=4x+6 2y=8x+12 tell weather is has one solution infinite solution or no solution

Which substance is a heterogeneous mixture? Cereal Silver Nickel Shampoo

Papessa [141]

It's definitely cereal because you can see the different contents, making it heterogeneous. The rest of the options, whether mixtures or natural elements, are homogeneous because all the contents come together nicely.

7 0

3 years ago

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Simplify it. 2(3-4y)

Tcecarenko [31]

Answer:

6-8y why it needs 20

Step-by-step explanation:

2*3=6

2*-4y=-8y

5 0

2 years ago

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Grandpa Ernie is shrinking! Over the past 4 years his height decreased by a total of 2.4 cm.It decreased by the same amount each

Nuetrik [128]

Your answer would be -0.6 cm.

just take -2.4/4

= -0.6

It is -2.4 because his height decreased each year.

Hope helps!-Aparri

6 0

3 years ago

What is the solution of the system? Use elimination.

sweet [91]

Answer:

The solutions to the system of the equations by the elimination method will be:

$x=2,\:z=-1,\:y=2$

Step-by-step explanation:

Given the system of the equations

$2x\:+\:2y\:+z\:=\:7$

$-x-\:y\:+z\:=\:-5$

$x+3y-4z=12$

solving the system of the equations by the elimination method

$\begin{bmatrix}2x+2y+z=7\\ -x-y+z=-5\\ x+3y-4z=12\end{bmatrix}$

$\mathrm{Multiply\:}-x-y+z=-5\mathrm{\:by\:}2\:\mathrm{:}\:\quad \:-2x-2y+2z=-10$

$\begin{bmatrix}2x+2y+z=7\\ -2x-2y+2z=-10\\ x+3y-4z=12\end{bmatrix}$

$-2x-2y+2z=-10$

$+$

$\underline{2x+2y+z=7}$

$3z=-3$

$\begin{bmatrix}2x+2y+z=7\\ 3z=-3\\ x+3y-4z=12\end{bmatrix}$

$2x+6y-8z=24$

$-$

$\underline{2x+2y+z=7}$

$4y-9z=17$

$\begin{bmatrix}2x+2y+z=7\\ 3z=-3\\ 4y-9z=17\end{bmatrix}$

Rearranging the equations

$\begin{bmatrix}2x+2y+z=7\\ 4y-9z=17\\ 3z=-3\end{bmatrix}$

solve $3z=-3$ for z:

$z=-1$

$\mathrm{For\:}4y-9z=17\mathrm{\:plug\:in\:}z=-1$

solve $4y-9\left(-1\right)=17$ for y:

$4y-9\left(-1\right)=17$

$4y+9=17$

$4y=8$

$y=2$

$\mathrm{For\:}2x+2y+z=7\mathrm{\:plug\:in\:}z=-1,\:y=2$

solve $2x+2\cdot \:2-1=7$ for x:

$2x+2\cdot \:2-1=7$

$2x+3=7$

$2x=4$

$x=2$

Therefore, the solutions to the system of the equations by the elimination method will be:

$x=2,\:z=-1,\:y=2$

5 0

2 years ago

Suppose u1, u2, ..., un are independent random variables and for every i = 1, ..., n, ui has a uniform distribution over [0, 1].

sattari [20]

$Z=U_{(1)}=\min\{U_1,\ldots,U_n\}$

has CDF

$F_Z(z)=1-(1-F_{U_i}(z))^n$

where $F_{U_i}(u_i)$ is the CDF of $U_i$ . Since $U_i$ are iid. with the standard uniform distribution, we have

$F_{U_i}(u_i)=\begin{cases}0&\text{for }u_i$

and so

$F_Z(z)=1-(1-F_{U_i}(z))^n=\begin{cases}0&\text{for }z$

Differentiate the CDF with respect to $z$ to obtain the PDF:

$f_Z(z)=\dfrac{\mathrm dF_Z(z)}{\mathrm dz}=\begin{cases}n(1-z)^{n-1}&\text{for }0$

i.e. $Z$ has a Beta distribution $\beta(1,n)$ .

3 0

2 years ago