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Harrizon [31]
3 years ago
9

The opposite of cubing is?

Mathematics
2 answers:
Ber [7]3 years ago
5 0

Answer:

cube rooting?

Step-by-step explanation:

like the cubed root of something

muminat3 years ago
3 0

Answer:

cube root

the opposite of cubing a number is finding the cube root

Step-by-step explanation:

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Find the measure of c.<br> (1<br> 27<br> O A. 31.6<br> B. 27<br> C. 63<br> D. 126
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Answer:

The answer is

The measure of c is 63

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Factor out the greatest common factor 2b^2+6b
goldfiish [28.3K]

Answer:

2b

Step-by-step explanation:

Identify the greatest common factors of 2 and 6, the answer is 2

identify the greatest common between b^2 and b, the answer is b

ao therefore the greatest common factor is 2b.

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Urgent!!!! not worried about a but i need b and #4
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b) The surface area is 564.5. Picture below.

4. Three possibilities.

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Formula for volume of sphere: 4/3πr^3

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I used substitution on this website https://www.omnicalculator.com/math/volume

Just plug in the 4.18879 at the cylinder volume and put in a random number in the radius or height whichever you want then it'll give you the one you left blank. You'll find three possibilities for the radius and height of 4.18879 volume.

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3 years ago
He solution to the initial value problem x′′+2x′+26x=5cos(4t),x(0)=0,x′(0)=0 x″+2x′+26x=5cos⁡(4t),x(0)=0,x′(0)=0 is the sum of t
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A person purchased a slot machine and tested it by playing it 1,137 times. There are 10 different categories of outcomes, includ
ivann1987 [24]

Answer:

p_v= P(\chi^2_{9}>11.517)=0.2419

And on this case if we see the significance level given \alpha=0.1 we see that p_v>alpha so we fail to reject the null hypothesis that the observed outcomes agree with the expected frequencies at 10% of significance.

Step-by-step explanation:

A chi-square goodness of fit test determines if a sample data obtained fit to a specified population.

p_v represent the p value for the test

O= obserbed values

E= expected values

The system of hypothesis for this case are:

Null hypothesis: O_i = E_i[/tex[Alternative hypothesis: [tex]O_i \neq E_i

The statistic to check the hypothesis is given by:

\chi^2 =\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

On this case after calculate the statistic they got: \chi^2 = 11.517

And in order to calculate the p value we need to find first the degrees of freedom given by:

df=n-1=10-1=9, where k represent the number of levels (on this cas we have 10 categories)

And in order to calculate the p value we need to calculate the following probability:

p_v= P(\chi^2_{9}>11.517)=0.2419

And on this case if we see the significance level given \alpha=0.1 we see that p_v>alpha so we fail to reject the null hypothesis that the observed outcomes agree with the expected frequencies at 10% of significance.

6 0
3 years ago
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