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Lemur [1.5K]
3 years ago
13

4. Solve. x² – 81 = 0 (1 point) 0 –9 –9, 9 9

Mathematics
2 answers:
astra-53 [7]3 years ago
7 0

Answer:

–9, 9

Step-by-step explanation:

x² – 81 = 0

Add 81 to each side

x² – 81+81 = 0+81

x^2 = 81

Take the square root of each side

sqrt(x^2) = ± sqrt(81)

x = ± 9

Rudik [331]3 years ago
5 0

x^2 - 81 = 0. Add 81 to each side.

x^2 = 81. Take the square root of each side.

x = 9, -9

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nadezda [96]
The answer to that would be “169”
3 0
3 years ago
A group of 12 students goes on a school field trip, 6 are in third grade. which fraction is equivalent to 6 12
Elis [28]

The fraction which is equivalent to 6/12 is 1/2

What does a fraction mean?

In the first place, fraction is a numerical quantity or relationship where one number is expressed in terms of another.

In order to determine the equivalence of 6/12 in fraction , we need reduce 6/12 to the lowest term, since 6 is common to 6 and 12 and that 6 divided by gives 1 and 12/6 gives 2, which means that we are left 1/2

The correct fraction which is equivalent to 6/12 is 1/2

Find out more about fraction on:brainly.com/question/5243429

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Full question:

A group of 12 students goes on a school field trip, 6 are in third grade. which fraction is equivalent to 6/12?

(A) 1/3

(B)1/4

(C) 1/6

(D) 1/2

5 0
2 years ago
WILL GIVE BRAINLIEST
Natasha_Volkova [10]

Answer:

see explanation

Step-by-step explanation:

In any circle the ratio of the arc length to the circumference of the circle is equal to the degree measure of the arc to 360°

3 0
3 years ago
Medical scientists study the effect of acute infection on tissue-specific immunity. In a collection of experiments under the sam
Serjik [45]

Answer:

The 95% confidence interval  for the true proportion of mice that will test positive under similar conditions is (0.5291, 0.6429).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

Z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

In a collection of experiments under the same conditions, 44 of 75 mice test positive for lymphadenopathy. This means that n = 75 and \pi = \frac{44}{75} = 0.586.

Compute a 95% confidence interval for the true proportion of mice that will test positive under similar conditions.

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.586 - 1.96\sqrt{\frac{0.586*0.414}{75}} = 0.5291

The upper limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.586 + 1.96\sqrt{\frac{0.586*0.414}{75}} = 0.6429

The 95% confidence interval  for the true proportion of mice that will test positive under similar conditions is (0.5291, 0.6429).

7 0
3 years ago
4
Mazyrski [523]

Answer:

the answer is 15/4

Step-by-step explanation:

all you have to do is take the independent variable and put the sign in between.

6 0
3 years ago
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