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MrMuchimi
3 years ago
10

How do you change inches to meters

Mathematics
1 answer:
zimovet [89]3 years ago
5 0

Answer:

there are 39.3701 inches in a meter if it is asking how many inches are in blank meters do the number of meters times the number i mentioned earlier

hoped this helped, have a nice day

Step-by-step explanation:

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The College Board SAT college entrance exam consists of three parts: math, writing and critical reading (The World Almanac 2012)
Wittaler [7]

Answer:

Yes, there is a difference between the population mean for the math scores and the population mean for the writing scores.

Test Statistics =   \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1 .

Step-by-step explanation:

We are provided with the sample data showing the math and writing scores for a sample of twelve students who took the SAT ;

Let A = Math Scores ,B = Writing Scores  and D = difference between both

So, \mu_A = Population mean for the math scores

       \mu_B = Population mean for the writing scores

 Let \mu_D = Difference between the population mean for the math scores and the population mean for the writing scores.

            <em>  Null Hypothesis, </em>H_0<em> : </em>\mu_A = \mu_B<em>     or   </em>\mu_D<em> = 0 </em>

<em>      Alternate Hypothesis, </em>H_1<em> : </em>\mu_A \neq  \mu_B<em>      or   </em>\mu_D \neq<em> 0</em>

Hence, Test Statistics used here will be;

            \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1    where, Dbar = Bbar - Abar

                                                               s_D = \sqrt{\frac{\sum D_i^{2}-n*(Dbar)^{2}}{n-1}}

                                                               n = 12

Student        Math scores (A)          Writing scores (B)         D = B - A

     1                      540                            474                                   -66

     2                      432                           380                                    -52  

     3                      528                           463                                    -65

     4                       574                          612                                      38

     5                       448                          420                                    -28

     6                       502                          526                                    24

     7                       480                           430                                     -50

     8                       499                           459                                   -40

     9                       610                            615                                       5

     10                      572                           541                                      -31

     11                       390                           335                                     -55

     12                      593                           613                                       20  

Now Dbar = Bbar - Abar = 489 - 514 = -25

 Bbar = \frac{\sum B_i}{n} = \frac{474+380+463+612+420+526+430+459+615+541+335+613}{12}  = 489

 Abar =  \frac{\sum A_i}{n} = \frac{540+432+528+574+448+502+480+499+610+572+390+593}{12} = 514

 ∑D_i^{2} = 22600     and  s_D = \sqrt{\frac{\sum D_i^{2}-n*(Dbar)^{2}}{n-1}} = \sqrt{\frac{22600 - 12*(-25)^{2} }{12-1} } = 37.05

So, Test statistics =   \frac{Dbar - \mu_D}{\frac{s_D}{\sqrt{n} } } follows t_n_-  _1

                            = \frac{-25 - 0}{\frac{37.05}{\sqrt{12} } } follows t_1_1   = -2.34

<em>Now at 5% level of significance our t table is giving critical values of -2.201 and 2.201 for two tail test. Since our test statistics doesn't fall between these two values as it is less than -2.201 so we have sufficient evidence to reject null hypothesis as our test statistics fall in the rejection region .</em>

Therefore, we conclude that there is a difference between the population mean for the math scores and the population mean for the writing scores.

8 0
3 years ago
Find the area of the shape shown below
ra1l [238]

Answer:

18 MARK AS BRAINLIEST OR ELSE!!!!

Step-by-step explanation:

area = 1/2h(sum of bases)

area = 1/2x3(3+9)

area = 1/2 of 36

area = 18

3 0
2 years ago
An amount of $290000 is borrowed for a period of 25 years at an interest rate of 4%
Serhud [2]

Answer:

nice

Step-by-step explanation:

7 0
2 years ago
I'm having trouble figuring out what the equation is for the trend line and what the slope is
Talja [164]

Answer:

The equation for the trend line would be y = -1/100x + 25

Step-by-step explanation:

In order to find the trend line, we first need to find the slope. To do so, we need to find two points on the line. The points we'll use are (0, 25) and (2500, 0). Next, we use the slope formula.

m(slope) = (y2 - y1)/(x2 - x1)

m = (0 - 25)/(2500 - 5)

m = -25/2500

m = -1/100

Now that we have this we can use the slope and the intercept in slope intercept form to model the trend line.

y = mx + b

y = -1/100x + 25

3 0
3 years ago
Which expression is equivalent to (4g3h2k4)3
RSB [31]

Answer:

d) 8g^{6}h^{4}  k^{12}  - (h^{25} k^{15} )

      \frac{(4g^{3} h^{2}k^{4} )^{3}  }{8g^{3}h^{2}  } - (h^{5} k^{3} )^{5}    = 8g^{6}h^{4}  k^{12}  - (h^{25} k^{15} )

Step-by-step explanation:

<u><em>Explanation</em></u>

Given expression

           =     \frac{(4g^{3} h^{2}k^{4} )^{3}  }{8g^{3}h^{2}  } - (h^{5} k^{3} )^{5}

By using

        (ab)ⁿ = aⁿbⁿ

         \frac{a^{m} }{a^{n} } = a^{m-n}

   =     \frac{(4)^{3} g^{9} h^{6}k^{12} )  }{8g^{3}h^{2}  } - (h^{5} k^{3} )^{5}

After simplification , we get

  = 8g^{9}g^{-3} h^{6} h^{-2} k^{12}  - (h^{5} k^{3} )^{5}

 = 8g^{9-3}h^{6-2}  k^{12}  - (h^{5} k^{3} )^{5}

= 8g^{6}h^{4}  k^{12}  - (h^{25} k^{15} )

3 0
2 years ago
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