Answer:
either x or y must equal 0
Step-by-step explanation:
ts given that xy = 0
Remember that product of two numbers can be zero only if:
Both of them are zero or Either of them is zero as zero multiplied to any non-zero number will always be equal to zero. This is known as Zero Product Property.
So, if the product of x and y is equal to 0 there are two possibilities:
Both x and y are equal to 0
Either x or y must be equal to 0
Note that the condition both x and y are equal to zero is not a must condition, because even if one of them is equal to zero, the entire expression will be equal to zero.
Hence, the condition which has to be true in all cases for xy = 0 is:
either x or y must equal 0
25^2=7^2 + x^2
49 + x^2 = 625
x^2= 576
square both sides
x=24
624 is how much is deducted from his pay every month
The division is using extra zeros.
2 * 16 = 32, but 3200 was placed below 3426.
Now 1 * 16 = 16, so 160 goes below 226.
The number that goes in the box is 160.
Answer:
Option D
Step-by-step explanation:
Given expression has been given as,
![\sqrt[5]{224x^{11}y^8}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B224x%5E%7B11%7Dy%5E8%7D)
![\sqrt[5]{224x^{11}y^8}=\sqrt[5]{2\times 2\times 2\times 2\times 2\times 7(x^{11})(y^8)}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B224x%5E%7B11%7Dy%5E8%7D%3D%5Csqrt%5B5%5D%7B2%5Ctimes%202%5Ctimes%202%5Ctimes%202%5Ctimes%202%5Ctimes%207%28x%5E%7B11%7D%29%28y%5E8%29%7D)
![=\sqrt[5]{(2^5)\times (7)(x^{10}\times x)(y^5\times y^3)}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B5%5D%7B%282%5E5%29%5Ctimes%20%287%29%28x%5E%7B10%7D%5Ctimes%20x%29%28y%5E5%5Ctimes%20y%5E3%29%7D)
![=2x^2y\sqrt[5]{7xy^3}](https://tex.z-dn.net/?f=%3D2x%5E2y%5Csqrt%5B5%5D%7B7xy%5E3%7D)
Option D will be the answer.
