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aliya0001 [1]
3 years ago
13

Someone help please???

Mathematics
1 answer:
algol [13]3 years ago
3 0
The things tht the people alwys thuingso do with the babayt
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A lead ball weighs 326 grams. Find the radius of the ball to the nearest tenth of a<br> centimeter.
rjkz [21]

Answer:

1.9cm

Step-by-step explanation:

The density d of a material is related to its mass m and volume V as follows;

d = \frac{m}{V}             ------------------(i)

The material in question here is the lead ball.

Now, from known experiment;

the density of lead is <em>11.34g/cm³</em>

From the question, the weight/mass of the lead ball is <em>326g</em>

Substitute these values into equation (i) as follows;

11.34 = \frac{326}{V}

V = \frac{326}{11.34}

V = 28.75cm³

Now, since the ball is of course spherical, we can get the radius by using the following relation from the volume of a sphere;

V = \frac{4}{3} \pi r^3          [V = volume, r = radius]

V = 28.75cm³

=> 28.75 = \frac{4}{3} \pi r^3

=> 3 x 28.75 = 4 π r³

=> 86.25 = 4 π r³

=> 21.5625 = π r³      [Take π = 3.142]

=> 21.5625 = (3.142) r³      [divide both sides by 3.142]

=> 6.86 = r³              [Take the cube root of both sides]

=> ∛6.86 = ∛r³

=> 1.90 = r

Therefore, the radius is 1.9cm to the nearest tenth

5 0
3 years ago
Which of these prevents conduction from occurring?
Brrunno [24]

Answer: equal temperatures :)

8 0
3 years ago
Read 2 more answers
hey ppl i forgot to add the drop down options on my last question so i made a new one with the options
Kipish [7]

Use the commutative Property of Addition to  add the last two terms first.

9 + (-17) + (-9) = -17

Hope this helps!! Good luck. :)

3 0
3 years ago
If segment EF = 6 and segment FG = 3, which of the following statements are enough to prove that triangles EFI and GFH are simil
klemol [59]

Answer:

lines EI and HG are parallel

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional

In this problem

If triangles EFI and GFH are similar

then

\frac{EF}{FG}=\frac{FI}{FH}=\frac{EI}{GH}

substitute the given values

\frac{6}{3}=\frac{FI}{FH}=\frac{EI}{GH}

2=\frac{FI}{FH}=\frac{EI}{GH}

If lines EI and HG are parallel

then the triangles are similar by AA Similarity Theorem

therefore

lines EI and HG are parallel

3 0
3 years ago
Read 2 more answers
Please help me. Show work
Goryan [66]
What hell there is nothings ??
7 0
3 years ago
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