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Angelina_Jolie [31]
3 years ago
6

Express 2,750,389 in scientific notation

Mathematics
1 answer:
hichkok12 [17]3 years ago
5 0
That method of representing the number would produce ...

           2.750389 x 10⁶  .
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What is the value of the expression 18-2×(4+3)
Vika [28.1K]
The value would be 4.

First, you have to do 4 + 3 because it's in parenteces. This equals 7
Secondly, you have to do 2 x 7, which is 14.
Last you have to do 18 - 14 which is 4.
3 0
4 years ago
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Which estimate (rounding to the nearest ten thousand or meet at thousand) is more accurate
wel
Rounding to the nearest thousand
for example, if the number is 104001. ten thousand would be 100000 while rounding to the nearest thousand would be 104000. accurate means closer to the correct answer, and the one rounded to the nearest thousand, 104000 is closer to the correct answer 104001 than the one rounded to ten thousand
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What is 3.6 subtract 0.7
hram777 [196]

Answer:

2.9

Step-by-step explanation:

3.6 - 0.7 = 2.9

6 0
3 years ago
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Suppose that the sitting​ back-to-knee length for a group of adults has a normal distribution with a mean of mu equals 24.4 in.
solong [7]

Answer:

P(X \geq 26.6) = 0.0336, which is greater than 0.01. So a back-to-knee length of 26.6 in. is not significantly high.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 24.4, \sigma = 1.2

In this problem, a value x is significantly high if:

P(X \geq x) = 0.01

Using these​ criteria, is a​ back-to-knee length of 26.6 in. significantly​ high?

We have to find the probability of the length being 26.6 in or more, which is 1 subtracted by the pvalue of Z when X = 26.6. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{26.6 - 24.4}{1.2}

Z = 1.83

Z = 1.83 has a pvalue of 0.9664.

1 - 0.9664 = 0.0336

P(X \geq 26.6) = 0.0336, which is greater than 0.01. So a back-to-knee length of 26.6 in. is not significantly high.

6 0
3 years ago
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