Answer:
\frac{13+\left(-3\right)^2+4\left(-3\right)+1-\left(-10-\left(-6\right)\right)}{\frac{\left(4+5\right)}{\left(4^2-3^2\left(4-3\right)-8\right)}+12}=5
Step-by-step explanation:
Hope this helps you out . Of solving for k then just set it equal to zero
Answer: 0.38065
in simpler terms x=± 0.145 =±0.38065
Step-by-step explanation: -490x2+71 = 0
Subtract 71 from both sides of the equation :
-490x2 = -71
Multiply both sides of the equation by (-1) : 490x2 = 71
Divide both sides of the equation by 490:
x2 = 71/490 = 0.145
When two things are equal, their square roots are equal. Taking the square root of the two sides of the equation we get:
x = ± √ 71/490
The equation has two real solutions
These solutions are x = ±√ 0.145 = ± 0.38065
