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3 years ago

2(x + 1 ) - 3(x + 5) ≥ 0 please solve!!

Mathematics

2 answers:

djverab [1.8K]3 years ago

8 0

Answer:

Step-by-step explanation:

2x + 2 -3x -15 > 0

-x-13 > 0

-x > 13

Answer: x < -13

siniylev [52]3 years ago

8 0

Answer:

$x\leq -13$

Step-by-step explanation:

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Answer:

Step-by-step explanation:

To prove: The sum of a rational number and an irrational number is an irrational number.

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steposvetlana [31]

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Step-by-step explanation:

The limit is:

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so, you have an indeterminate result. By using the l'Hôpital's rule you have:

$\lim_{x \to 0} \frac{a(x)}{b(x)}= \lim_{x \to 0} \frac{a'(x)}{b'(x)}$

by replacing, and applying repeatedly you obtain:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}= \lim_{x \to 0}\frac{3cosx-3}{21x^2}= \lim_{x \to 0}\frac{-3sinx}{42x}= \lim_{x \to 0}\frac{-3cosx}{42}\\\\ \lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{-3cos0}{42}=-\frac{1}{14}$

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