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nikdorinn [45]
3 years ago
13

Ammonia, NH3, can be classified as a base because in a chemical reaction with an acid, ammonia will

Biology
1 answer:
sleet_krkn [62]3 years ago
7 0
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
Below are the answers:

13. NH3 forms a base because it forms hydroxide ions in solution <span>14. butter does not dissolve, acid will lower the pH </span>
<span>15. electrolyte and will conduct</span>
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Properties of Light Lab
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Answer: please ask me for help and vote me brainliest :)

The intensity or refraction depends on the material

Explanation:

In the experiment, the purpose it to determine the effect of the material on the refraction index. The refraction index is the ration of the incident ray to the refracted ray. This relationship is known as Snell's law of refraction

where i and r are angles of incident an the refracted ray and n is the refractive index. The dense the material, the more the angle bends. This means that the angle of refraction, as measured by the protractor, is going to be large.

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2 years ago
Describe how urban development can increase flooding.
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Answer:The changes in land use associated with urban development affect flooding in many ways. Removing vegetation and soil, grading the land surface, and constructing drainage networks increase runoff to streams from rainfall and snowmelt.

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2 years ago
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4 years ago
What are the base pairs?
Roman55 [17]

Answer:

Adenine pairs with Thymine or Uracil, Cytosine pairs with Gaunine

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3 years ago
A 0.2 M solution of NaCl contains ________ g of NaCl in 1 l of ________.
Maksim231197 [3]

Answer:

11.7 g in 1 L of water.

Explanation:

Molarity (M) or Molar concentration is a measure used in chemistry for solutes in a solution.

It is defined as mol/ L (number of moles per litre).

0,2 M means we have 0,2 mol/ L

In order to know how many grams this means we need to look up the molecular weight of the solute. In this case NaCl: 58.443 g/mol

\frac{1 mol NaCl}{58.443 g} = \frac{0.2 mol}{X g}

X= \frac{(0.2 mol x 58.433 g}{1 mol}

X= 11.69 g

The solution has 11.69 g of NaCl in 1 L of water since its an adequate polar solvent for NaCl dissolution.

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3 years ago
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