Answer:
D(12) = 2,600 miles
It means a distance of 2,600 miles is already traveled from home after 12 hours
Step-by-step explanation:
To find D(12); all we have to do is to substitute the value of 12 for D
We have this as;
D(12) = 3260-55(12)
D(12) = 2,600
In the context of this problem, what this mean is that the distance away from home is 2,600 miles after traveling 12 hours
The following is true:
H(x) has a constant output of -2.50
G(x) is greater than -2.50 for x values less than -1
The input value for which g(x)=h(x) is between -1 and 0
So
1, 3, and 5 is true
Or
A, C, E is true
Solve the system of equations
using Cramer’s Rule.
1. Find the determinants:
![\Delta_x=\left|\begin{array}{cc}3 & -1\\-24 & -2\end{array}\right|=3\cdot (-2)-(-1)\cdot (-24)=-6-24=-30.](https://tex.z-dn.net/?f=%5CDelta_x%3D%5Cleft%7C%5Cbegin%7Barray%7D%7Bcc%7D3%20%26%20-1%5C%5C-24%20%26%20-2%5Cend%7Barray%7D%5Cright%7C%3D3%5Ccdot%20%28-2%29-%28-1%29%5Ccdot%20%28-24%29%3D-6-24%3D-30.)
![\Delta_y=\left|\begin{array}{cc}10 & 3\\5 & -24\end{array}\right|=10\cdot (-24)-3\cdot 5=-240-15=-255.](https://tex.z-dn.net/?f=%5CDelta_y%3D%5Cleft%7C%5Cbegin%7Barray%7D%7Bcc%7D10%20%26%203%5C%5C5%20%26%20-24%5Cend%7Barray%7D%5Cright%7C%3D10%5Ccdot%20%28-24%29-3%5Ccdot%205%3D-240-15%3D-255.)
2. Now find unknown variables:
![x=\dfrac{\Delta_x}{\Delta}=\dfrac{-30}{-15}=2,\\ \\y=\dfrac{\Delta_y}{\Delta}=\dfrac{-255}{-15}=17.](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7B%5CDelta_x%7D%7B%5CDelta%7D%3D%5Cdfrac%7B-30%7D%7B-15%7D%3D2%2C%5C%5C%20%5C%5Cy%3D%5Cdfrac%7B%5CDelta_y%7D%7B%5CDelta%7D%3D%5Cdfrac%7B-255%7D%7B-15%7D%3D17.)
Answer: the minimum number of determinants that are needed to solve for all unknowns in the system of linear equations is 3.
Answer:
x = 2
y =7
Step-by-step explanation:
the system of linear equation will be solve using substitution method,
let
Y=3x+1.............................................. equation 1
Y=2x+3.............................................. equation 2
substitute equation 1 into equation 2
3x + 1 = 2x + 3
combine the like terms
3x+1 -2x = 3
x = 3 -1
x = 2
put the value of x=2 in either equation 1 or 2
Y=2x+3.............................................. equation 2
y = 2(2) + 3
y = 4 + 3
y = 7