Answer:
Step-by-step explanation:
Corresponding scores before and after taking the course form matched pairs.
The data for the test are the differences between the scores before and after taking the course.
μd = scores before taking the course minus scores before taking the course.
a) For the null hypothesis
H0: μd ≥ 0
For the alternative hypothesis
H1: μd < 0
b) We would assume a significance level of 0.05. The P-value from the test is 0.65. The p value is high. It increases the possibility of accepting the null hypothesis.
Since alpha, 0.05 < than the p value, 0.65, then we would fail to reject the null hypothesis. Therefore, it does not provide enough evidence that scores after the course are greater than the scores before the course.
c) The mean difference for the sample scores is greater than or equal to zero
Answer:
No, because the expression s/4 - 16. In the word formed she times 4 and the letter, she should have to dived it.
Step-by-step explanation:
No, because the expression s/4 - 16. In the word formed she times 4 and the letter, she should have to dived it.
Answer:
This appears to be exponential based on the plot of these points
Step-by-step explanation:
See image
Answer:
good u?
Step-by-step explanation:
