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fredd [130]
3 years ago
15

Part B:

Mathematics
1 answer:
Marina86 [1]3 years ago
8 0
Negative 72.75 is your product. It is very simple once you understand it.
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Differential Equations and Slope Fields
stiv31 [10]

Answer:

9x2−x4+y(x2+9)2x(x2+9)2

Step-by-step explanation:

7 0
3 years ago
Every day your friend commutes to school on the subway at 9 AM. If the subway is on time, she will stop for a $3 coffee on the w
Shtirlitz [24]

Answer:

1.02% probability of spending 0 dollars on coffee over the course of a five day week

7.68% probability of spending 3 dollars on coffee over the course of a five day week

23.04% probability of spending 6 dollars on coffee over the course of a five day week

34.56% probability of spending 9 dollars on coffee over the course of a five day week

25.92% probability of spending 12 dollars on coffee over the course of a five day week

7.78% probability of spending 12 dollars on coffee over the course of a five day week

Step-by-step explanation:

For each day, there are only two possible outcomes. Either the subway is on time, or it is not. Each day, the probability of the train being on time is independent from other days. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

The probability that the subway is delayed is 40%. 100-40 = 60% of the train being on time, so p = 0.6

The week has 5 days, so n = 5

She spends 3 dollars on coffee each day the train is on time.

Probabability that she spends 0 dollars on coffee:

This is the probability of the train being late all 5 days, so it is P(X = 0).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{5,0}.(0.6)^{0}.(0.4)^{5} = 0.0102

1.02% probability of spending 0 dollars on coffee over the course of a five day week

Probabability that she spends 3 dollars on coffee:

This is the probability of the train being late for 4 days and on time for 1, so it is P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{5,1}.(0.6)^{1}.(0.4)^{4} = 0.0768

7.68% probability of spending 3 dollars on coffee over the course of a five day week

Probabability that she spends 6 dollars on coffee:

This is the probability of the train being late for 3 days and on time for 2, so it is P(X = 2).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{5,2}.(0.6)^{2}.(0.4)^{3} = 0.2304

23.04% probability of spending 6 dollars on coffee over the course of a five day week

Probabability that she spends 9 dollars on coffee:

This is the probability of the train being late for 2 days and on time for 3, so it is P(X = 3).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{5,3}.(0.6)^{3}.(0.4)^{2} = 0.3456

34.56% probability of spending 9 dollars on coffee over the course of a five day week

Probabability that she spends 12 dollars on coffee:

This is the probability of the train being late for 1 day and on time for 4, so it is P(X = 4).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 4) = C_{5,4}.(0.6)^{4}.(0.4)^{1} = 0.2592

25.92% probability of spending 12 dollars on coffee over the course of a five day week

Probabability that she spends 15 dollars on coffee:

Probability that the subway is on time all days of the week, so P(X = 5).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{5,5}.(0.6)^{5}.(0.4)^{0} = 0.0778

7.78% probability of spending 12 dollars on coffee over the course of a five day week

8 0
4 years ago
Sarah serves at a restaurant and makes 20% of what she sells as tips. Her base salary is $10.20an hour. Each hour she sells an a
Dimas [21]

Sara works 46 hours per week

9 hours are overtime and 37 hours are regular time

pay rate at time and a half: 10.20∗1.5=15.30

regular hours plus overtime pay

37∗10.20=377.40

9∗15.30=137.70

Income due to tips

Total hours worked∗60per hour∗20%

46∗60∗.20=552

Weekly Income=Hourly income + tips

Weekly Income=377.40+137.70+552.00

Weekly Income=1067.10

Annual income=Weekly income∗52

Annual income=55489.20

4 0
3 years ago
What is the total number of different 10-letter arrangemenis that can be
sp2606 [1]

Answer:

151200

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Which choice is equivalent to the product below when x > 0?
anastassius [24]

The product below is equivalent when x > 0 is <u>1/9</u>

       

<h3>Resolution - Explanation</h3>

Square root is a real number x multiplied by itself - which results in a perfect value, where it is possible to calculate the real proof (which is the square root).

             

Given the expression, \large \sf \sqrt{\dfrac{1}{x^{2} } }  \cdot \sqrt{\dfrac{x^{2} }{81} }, first step: we will calculate the root of the numerator and denominator of this fraction:

<u />

<u />\\\large \sf \sqrt{\dfrac{1}{x^{2} } }  \cdot \sqrt{\dfrac{x^{2} }{81} }

\large \sf \dfrac{\sqrt{1} }{\sqrt{x^{2} } }  \rightarrow \dfrac{1}{x}

\large \sf \dfrac{\sqrt{x^{2} } }{\sqrt{81 } }  \rightarrow \dfrac{x}{9}\\\\

Step two: rearranging the expression and canceling the common factors x, we will have,:

\\\large \sf \dfrac{1}{\not x} \cdot \dfrac{\not x}{9}

\pink{\boxed{\large \sf \dfrac{1}{9} }}\\

Therefore, the final answer to this multiplication will be 1/9.

6 0
2 years ago
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