<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em> </em><em>⤴</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>
W can be represented in the following equation: 14/tan 38°=w
Since tan 38 equals 0.78128563, we divide 14 by 0.78128563 which gives a value of 17.91
W= 17.91
W+X (which is the whole lenght) can be represented in the equation: w+x=14/tan 19°
So
17.9+X=14/0.34432761
we isolate for x and obtain
X= 40.65-17.9
X=22.75 (which we round to 22.8)
So the answer is option 4:
w = 17.9; x = 22.8
Answer:
Step-by-step explanation:
First, we find the LCD. It is 36. Multiply both sides by 36.
Answer:
D
Step-by-step explanation:
Answer:
The percent of the pairs that last longer than six months—that is, 180 days is 95.637%
Step-by-step explanation:
Mean = xbar = 208 days
Standard deviation = σ = 14
The standardized score for 180 days is the value minus the mean then divided by the standard deviation.
z = (x - xbar)/σ = (180 - 208)/14 = - 1.71
To determine the percent of boots that last longer than 180 days, we need this probability, P(x > 180) = P(z > (-1.71))
We'll use data from the normal probability table for these probabilities
P(x > 180) = P(z > (-1.71)) = 1 - P(z ≤ (-1.71)) = 1 - 0.04363 = 0.95637 = 95.637%