Find the missing area
1 answer:
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The area of the square of the leg 6 is 36 square units.
The area of the square of the leg 8 is 64 square units.
The area of the square of the hypotenuse square is 100 square units.
The length of the hypotenuse is 10 units.
Formula Used
Area of square, A =
Here, is the length of the side of the square.
Pythagoras Theorem is given as,
Here, are the hypotenuse, perpendicular, and the base of a right angle triangle respectively.
Area of the Square of the Leg 6
Length of the edge of the square = 6 units
Area of square = 6*6
= 36 square units
Area of the Square of the Leg 8
Length of the edge of the square = 8 units
Area of square = 8*8
= 64 square units
Area of the Hypotenuse Square and the Length of the Hypotenuse
Applying Pythagoras theorem,
Therefore, the area of the hypotenuse square is 100 square units and the length of the hypotenuse comes out to be10 units.
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Solve for the variable y (move the x to the right of equal with changed sign)
M is the coefficient before the x and b is the known number
-3y = -12 - 6x
Since the y can't be negative, multiply every term for -1, therefore change their sign
3y = 6x + 12
To find y, divide both terms for 3
y = 2x+4
Therefore your answer is y = 2x+4
M is the coefficient before the x and b is the known number
-3y = -12 - 6x
Since the y can't be negative, multiply every term for -1, therefore change their sign
3y = 6x + 12
To find y, divide both terms for 3
y = 2x+4
Therefore your answer is y = 2x+4