All categories

3 years ago

Arrange the following set of decimal numbers.

Mathematics

2 answers:

shtirl [24]3 years ago

8 0

Answer:

Step-by-step explanation:

I HOPE IT HELPS :)

vekshin13 years ago

6 0

The correct answer is 2.

You might be interested in

I wonder if I did #9 right and I’m having trouble with #10

yaroslaw [1]

Let's see....

QUESTION: Add. Write your answer as a mixed number in simplest form.

$6 \frac{7}{9} + 9 \frac{8}{9}$

1. Rewriting our equation with parts separated

<span><span> $=6+ \frac{7}{9} +9+ \frac{8}{9}$

</span></span>2. Solving the whole number parts

<span> $6+9=15$

</span>3. Solving the fraction parts

<span><span> $\frac{7}{9} + \frac{8}{9} = \frac{15}{9}$

</span></span>4. Reducing the fraction part, 15/9,

<span><span> $\frac{15}{9} = \frac{5}{3}$

</span></span>5. Simplifying the fraction part, 5/3,

<span><span> $\frac{5}{3} = 1\frac{2}{3}$

</span></span>6. Combining the whole and fraction parts

<span><span><span> $15+1+ \frac{2}{3} =16 \frac{2}{3}$

ANSWER: $16\frac{2}{3}$

Hope that helps!
</span></span></span>

8 0

3 years ago

Read 2 more answers

Explain how to find each root, with its multiplicity, for the polynomial y=x^5-27x^2.

Nuetrik [128]

The roots of $y = x^{5}-27\cdot x^{2}$ are 0 (multiplicity 2), -3 (multiplicity 1), $-\frac{3}{2}+i\,\frac{3\sqrt{3}}{2}$ (multiplicity 1) and $-\frac{3}{2}-i\,\frac{3\sqrt{3}}{2}$ (multiplicity 1).

The characteristics of the polynomial can be derived from algebraic techniques. Roots and multiplicity can be found by <em>factoring</em> the polynomial. The multiplicity is represented by a power binomial of the form:

$(x-r_{i})^{m},\,m \le n$ (1)

Where $n$ is the grade of the polynomial.

Now we proceed to factor the formula:

$y = x^{5}-27\cdot x^{2}$

$y = x^{2}\cdot (x^{3}-27)$

$y = x^{2}\cdot (x^{2}+3\cdot x +9)\cdot (x-3)$

Please notice that $x^{2}+3\cdot x + 9$ have two complex roots.

$y = x^{2}\cdot \left(x+\frac{3}{2}-i\,\frac{3\sqrt{3}}{2} \right)\cdot \left(x+\frac{3}{2}+i\,\frac{3\sqrt{3}}{3} \right)\cdot (x-3)$

The roots of $y = x^{5}-27\cdot x^{2}$ are 0 (multiplicity 2), -3 (multiplicity 1), $-\frac{3}{2}+i\,\frac{3\sqrt{3}}{2}$ (multiplicity 1) and $-\frac{3}{2}-i\,\frac{3\sqrt{3}}{2}$ (multiplicity 1).

We kindly invite to see this question on polynomials: brainly.com/question/1218505

7 0

2 years ago

A swimming pool had 2.52.52, point, 5 million liters of water in it. Some water evaporated, and then the pool only had 222 milli

pishuonlain [190]

Answer:20% i know because i had a question like this

8 0

2 years ago

Solve the triangle.

Angelina_Jolie [31]

Using the sine law of triangles to solve for angle C:

b / sin B = c / sin C

C = arcsin (c * sin B / b)
C = 30.7<span>°

Since interior angles of a triangle always add up to 180</span><span>°, we can use this to solve for angle A:

angle A = 180</span>° - 73° - 30.7<span>°
angle A = 76.3</span><span>°

Having solved for angle A, we can solve for side a using the sine law.

a / sin A = b / sin B

a = b * sin A / sin B
a = 15.2

Therefore, the correct answer is B.</span>

3 0

2 years ago

X to the 3rd power equals 343 what is x

Minchanka [31]

Your answers is
x equals 7

4 0

3 years ago

Read 2 more answers