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nata0808 [166]
3 years ago
5

Find (f*g)(x) when f(x)=x^2-7x+12 and g(x)=7/x^2-16

Mathematics
1 answer:
AleksandrR [38]3 years ago
7 0

Answer:

  (f\cdot g)(x)=\dfrac{7x-21}{x+4}

Step-by-step explanation:

(f\cdot g)(x)=f(x)\cdot g(x)=(x^2-7x+12)\cdot\dfrac{7}{x^2-16}\\\\=7\dfrac{(x-3)(x-4)}{(x+4)(x-4)}=\dfrac{7(x-3)}{x+4}\\\\=\dfrac{7x-21}{x+4}

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xxTIMURxx [149]

Answer:

26%

Step-by-step explanation:

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71.24 / 274 =0.26

0.26 * 100 = 26

8 0
3 years ago
The points (3,9) and (-3,-9) are plotted on the coordinate plane using the equation y= a•x. What is the value of a?
8_murik_8 [283]
A=3

The equation y=3x goes through both points

Hope I helped

5 0
3 years ago
Can anyone help me with this?
Neko [114]

Answer:

the answer would be 5

Step-by-step explanation:

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3 0
2 years ago
Order from greatest to least, 19/4, 45/10, 4 3/5.
pogonyaev

Answer:

45/10, 4 3/5, 19/4

Step-by-step explanation:

19/4 = 4.75

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Best of Luck!

3 0
3 years ago
Read 2 more answers
The 3rd and 6th term of a geometric progression are 9/2 and 243/16 respectively find the first term, common ratio, seventh term​
sashaice [31]

Answer:

Hello,

Step-by-step explanation:

Let\ (u_n)\ the\ geometric\ progression.\\\\r\ is\ the\ common\ ratio.\\\\u_3=u_0*r^3\\u_6=u_0*r^6\\\\\dfrac{u_6}{u_3} =r^3=\dfrac{\frac{243}{16} }{\frac{9}{2} } =\dfrac{27}{8} =(\frac{3}{2} )^3\\\\\boxed{r=\dfrac{3}{2} }\\\\\\u_3=u_1*r^2 \Longrightarrow\ u_1=\dfrac{u_3}{r^2} =\dfrac{\frac{9}{2} }{(\frac{3}{2^2}) } =2\\\\\\u_7=u_6*\dfrac{3}{2} =\dfrac{729}{32}

5 0
3 years ago
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