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AveGali [126]
3 years ago
7

In her last four games of golf, Maria has had scores of 76, 73, 70, and 67.

Mathematics
1 answer:
Mkey [24]3 years ago
4 0

Answer:

Maria's score be in her next (FIFTH) game  is 64 points.

Step-by-step explanation:

The scores obtained by Maria in four games  is :

76 , 73 , 70 and 67.

Now, from the  above data , we can see that:

The score of (FIRST GAME - SECOND GAME)  = 76 - 73  = 3 points

The score of (SECOND GAME - THIRD GAME)  = 73 - 70  = 3 points

The score of (THIRD GAME -FOURTH GAME)  = 70 - 67  = 3 points

So, continuing in the same way:

The score of (FOURTH GAME - FIFTH GAME)   = 3 points

or, 67  - Score of fifth game  = 3 points

or, Score of fifth game = 67 - 3  = 64 points.

Hence,  Maria's score be in her next (FIFTH) game  is 64 points.

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{\huge{\fcolorbox{yellow}{red}{\orange{\boxed{\boxed{\boxed{\boxed{\underbrace{\overbrace{\mathfrak{\pink{\fcolorbox{green}{blue}{Answer}}}}}}}}}}}}}

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<u>(</u><u>i</u><u>)</u><u> </u><u>We</u><u> </u><u>will</u><u> </u><u>use</u><u> </u><u>here</u><u> </u><u>geometric</u><u> </u><u>progression</u><u> </u><u>formula</u><u> </u><u>to</u><u> </u><u>find</u><u> </u><u>height</u><u> </u><u>an</u><u> </u><u>times</u>

{\blue{\sf{a_n = a {r}^{n - 1} }}} \\ \sf{a_n = 20 \times  { \frac{2}{3} }^{n - 1} }

(ii) <u>here</u><u> </u><u>we</u><u> </u><u>will</u><u> </u><u>use</u><u> </u><u>the</u><u> </u><u>sum</u><u> </u><u>formula</u><u> </u><u>of</u><u> </u><u>geometric</u><u> </u><u>progression</u><u> </u><u>for</u><u> </u><u>finding</u><u> </u><u>the</u><u> </u><u>total</u><u> </u><u>nth</u><u> </u><u>impact</u>

<u>\orange {\sf{S_n = a \times  \frac{(1 -  {r}^{n} )}{1 - r} }} \\  \sf S_n = 20 \times  \frac{1 -  ( { \frac{2}{3} })^{n}  }{1 -  \frac{2}{3} }  \\   \sf S_n = 20 \times  \frac{1 -  {( \frac{2}{3}) }^{n} }{ \frac{1}{3} }  \\  \sf S_n = 3 \times 20 \times  \{1 - ( { \frac{2}{3}) }^{n}  \} \\   \purple{\sf S_n = 60 \{1 -  { \frac{2}{3} }^{n}  \}}</u>

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