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babymother [125]
3 years ago
6

I need help for all of this problems!

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
4 0
A) All triangles add up to 180° so when given two angles, add those up and subtract them from 180° . That will give you the missing angle.

3-5) When you do A above, and receive the measurement of angle 1, it will also equal 2 and you can repeat A for missing angle 3

6-8) Find the missing angle next to 1, and then subtract that from 180°. That number is the answer for 1. 2 is 55 as its a complimentary (i think thats the right term) angle. Which means it is on the opposite side of an angle. I don't remember how to find 3 however, its been a few years since I've done triangles.
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Calculus A hard problem help please
dexar [7]
∑x = 1 + 2 + 3 + 4 + 5 + 6 = 21
∑y = 8 + 3 + 0 + 1 + 2 + 1 = 15
∑x^2 = 1 + 4 + 9 + 16 + 25 + 36 = 91
∑y^2 = 64 + 9 + 0 + 1 + 4 + 1 = 79
∑xy = 8 + 6 + 0 + 4 + 10 + 6 = 34

r = (n∑xy - ∑x∑y)/(sqrt(n∑x^2 - (∑x)^2)*sqrt(n∑y^2 - (∑y)^2)) = (6(34) - 21(15))/(sqrt(6(91) - (21)^2)*sqrt(6(79) - (15)^2)) = (204 - 315)/(sqrt(546 - 441)*sqrt(474 - 225)) = -111/(sqrt(105)*sqrt(249)) = -111/(10.25*15.78) = -111/161.7 = -0.68

3 0
3 years ago
Read 2 more answers
Explain why you cannot factor the trinomial <br> 2x^2+7x+10
Julli [10]
There are no factors of 20 that add up to 7.
Factors of 20 are:
1*20
2*10
4*5
5 0
3 years ago
Hi everyone... I am giving points... I repeat points
Snezhnost [94]

Answer:

why are you people giving them away???????

and btw how was your day?

and thanks fro the points

Step-by-step explanation:

4 0
2 years ago
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Steps to solve the equation 4n - 2n + 4 = -1 + 17
Liula [17]

4n-2n+4=-1+17

2n+4=-1+17

-1+17=16

2n+4=16

Move + 4 to the other side. Sign changes from +4 to -4

2n+4-4=16-4

2n=12

Divide by 2 for 2n and 12

2n/2=12/2

n=6

Check answer by using substitution method

4(6)-2(6)+4=16

24-12+4=16

12+4=16

16=16

Answer : n=6

3 0
3 years ago
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Classify the figure as a polyhedron or not polyhedron.
Step2247 [10]
It is a polyhedron (i think)
5 0
2 years ago
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