All categories

2 years ago

Use the tables to determine which function will eventually exceed the other, and provide your reasoning.

Mathematics

1 answer:

Vadim26 [7]2 years ago

6 0

Answer:

The answer is f(x) will eventually exceed g(x) because f(x) is an exponential function.

I just took the test and got it right.

Step-by-step explanation:

You might be interested in

Select 1 answer choices: sizes averages distances areas perimeters

hammer [34]

Answer:

sdfghjkl;

Step-by-step explanation:

asjty5d7u

hyjur6

fgiufctcuvty

86bvygf7

7 0

2 years ago

jon used a gift card to pay for an $18 shirt.The remaining balance on the card is $28.write and solve an equation that represent

denis-greek [22]

Take note that they spent $18 afterwards having $28 on the card so they're spending money off the card so...

x-18=28

would be the equation for this and to solve do the following.

First add 18 to both sides making the equation.

x=46

7 0

2 years ago

Read 2 more answers

HELP ME PLESA IM DESPO PAKJDCD PLS HELP

WARRIOR [948]

Answer:

144 cm²

Step-by-step explanation:

A prism's surface has 2 triangles & 3 rectangles.

In both the triangles , length of :

Perpendicular = 4 cm

Base = 6 cm

So , Area of both triangles = $2(\frac{1}{2} * Base * Perpendicular) = 2(\frac{1}{2}* 6 * 4) = 24 cm^2$

In the 3 rectangles ,

Length = 8 cm

Width = 5 cm

So , Area of the rectangles = $3( Length * Width) = 3(8 * 5) = 120 cm^2$

Hence the total surface area of the prism is = 120 + 24 =144 cm²

6 0

2 years ago

2. Which of the following methods can't be used to find the zeros of a function?

ser-zykov [4K]

Answer:

The correct option is;

Substitute x = 0 in the function and solve for f(x)

Step-by-step explanation:

The zeros of a function are the values of x which produces the value of 0 when substituted in the function

It is the point where the curve or line of the function crosses the x-axis

A. Substituting x = 0 will only give the point where the curve or line of the function crosses the y-axis,

Therefore, substituting x = 0 in the function can't be used to find the zero's of a function

B. Plotting a graph of the table of values of the function will indicate the zeros of the function or the point where the function crosses the x-axis

C. The zero product property when applied to the factors of the function equated to zero can be used to find the zeros of a function

d, The quadratic formula can be used to find the zeros of a function when the function is written in the form a·x² + b·x + c = 0

5 0

3 years ago

Find the solution of the given initial value problem. ty' + 2y = sin t, y π 2 = 9, t > 0 y(t) =

Helen [10]

For the ODE

$ty'+2y=\sin t$

multiply both sides by t so that the left side can be condensed into the derivative of a product:

$t^2y'+2ty=t\sin t$

$\implies(t^2y)'=t\sin t$

Integrate both sides with respect to t :

$t^2y=\displaystyle\int t\sin t\,\mathrm dt=\sin t-t\cos t+C$

Divide both sides by $t^2$ to solve for y :

$y(t)=\dfrac{\sin t}{t^2}-\dfrac{\cos t}t+\dfrac C{t^2}$

Now use the initial condition to solve for C :

$y\left(\dfrac\pi2\right)=9\implies9=\dfrac{\sin\frac\pi2}{\frac{\pi^2}4}-\dfrac{\cos\frac\pi2}{\frac\pi2}+\dfrac C{\frac{\pi^2}4}$

$\implies9=\dfrac4{\pi^2}(1+C)$

$\implies C=\dfrac{9\pi^2}4-1$

So the particular solution to the IVP is

$y(t)=\dfrac{\sin t}{t^2}-\dfrac{\cos t}t+\dfrac{\frac{9\pi^2}4-1}{t^2}$

$y(t)=\dfrac{4\sin t-4t\cos t+9\pi^2-4}{4t^2}$

6 0

2 years ago