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3 years ago

8

Construct a truth table for the statement: (p v q) v (~p ^ q) -> q

1 answer:

Gnom [1K]3 years ago

8 0

Step-by-step explanation:

We have the following statement $(p\lor q)\lor(\lnot p \land q) \rightarrow q$

A truth table shows how the truth or falsity of a compound statement depends on the truth or falsity of the simple statements from which it's constructed.

The simple statements from the statement given are:

$\lnot p$ , $p\lor q$ , $\lnot p \land q$ , and $(p\lor q)\lor(\lnot p \land q)$

This is the truth table.

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The sum of two polynomials is 8d5 – 3c3d2 + 5c2d3 – 4cd4 + 9. If one addend is 2d5 – c3d2 + 8cd4 + 1, what is the other addend?

MatroZZZ [7]

Answer:

a. $x = 6d^5 - 2c^3d^2 + 5c^2d^3 - 12cd^4 + 8$

Step-by-step explanation:

Given that

$8d^5 + 3c^3d62 + 5c^2d^3 - 4cd^4 + 9$

Now

if one is added i.e.

$2d^5 - c^3d^2 + 8cd^4 + 1$

Now let us assume the other polynomial be x

So,

$8d^5 + 3c^3d62 + 5c^2d^3 - 4cd^4 + 9 = x + (2d^5 - c^3d^2 + 8cd^4 + 1)\\\\x = 8d^5 + 3c^3d62 + 5c^2d^3 - 4cd^4 + 9 - (2d^5 - c^3d^2 + 8cd^4 + 1)\\\\$

$x = (8d^5 - 2d^5) + (-3c^3d^2 + c^3d^2) + 5c^2d^3+ (-4cd^4-8cd^4) + (9-1)\\\\x = 6d^5 - 2c^3d^2 + 5c^2d^3 - 12cd^4 + 8$

8 0

3 years ago

Read 2 more answers

Rewrite the equation in Ax+By=C form

Ksju [112]

Ax + By = C form of the given equation is –6x + y = –28.

Solution:

Given equation is y – 2 = 6(x – 5).

To write the equation in Ax + By = C format:

y – 2 = 6(x – 5)

y – 2 = 6x – 30

Add 2 on both sides of the equation.

y – 2 + 2 = 6x – 30 + 2

y = 6x – 28

Subtract 6x from both sides of the equation.

y – 6x = 6x – 28 – 6x

y – 6x = –28

Arrange the terms in the equation.

–6x + y = –28

This is in the form of Ax + By = C.

Here A = –6, B = 1 and C = –28.

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3 years ago

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Lera25 [3.4K]

Answer:

The answer is 7 x + 3 =24 because its a problem solving

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3 years ago

Another quadratic formula and the discriminant problem that I am stuck on. the answer is {2, 1/2}

Alina [70]

Answer:

See explanation

Step-by-step explanation:

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Hope this helps!

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vfiekz [6]

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3 years ago

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