1w-4= 4-1w
+1w +1w
——————
2w-4=4
+4 +4
—————
2w=8
———
2. 2
w= 4
n, n+1 - two consecutive integers
n(n + 1) = 50 <em>use distributive property</em>
n² + n = 50 <em>subtract 50 from both sides</em>
n² + n - 50 = 0
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ax² + bx + c =0
if b² - 4ac > 0 then we have two solutions:
[-b - √(b² - 4ac)]/2a and [-b - √(b² + 4ac)]/2a
if b² - 4ac = 0 then we have one solution -b/2a
if b² - 4ac < 0 then no real solution
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n² + n - 50 = 0
a = 1, b = 1, c = -50
b² - 4ac = 1² - 4(1)(-50) = 1 + 200 = 201 > 0 → two solutions
√(b² - 4ac) = √(201) - it's the irrational number
Answer: There are no two consecutive integers whose product is 50.
Step-by-step explanation:
As < A and < B are vertical angles so
<A = < B
5x + 12 = 6x - 11
6x - 5x = 12 + 11
x = 23
Hope it will help :)❤
<h3> Hope this attachment helps u</h3>
