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3 years ago

How do I solve a system of equations using substitution?

Mathematics

1 answer:

Sonbull [250]3 years ago

8 0

Answer:

A way to solve a linear system algebraically is to use the substitution method. The substitution method functions by substituting the one y-value with the other. We're going to explain this by using an example. We can substitute y in the second equation with the first equation since y = y.

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Determine which line is perpendicular to y = - 7/5x-2.

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Answer:

y = 5/7 x - 6

Step-by-step explanation:

For two lines to be perpendicular, the product of their slope must be -1

The slope of the given function is -7/5

Let the slope of the required function be m

m * -7/5 = -1

7/5 m = 1

7 = 5m

m = 5/7

The slope of the line perpendicular to the line is 5/7

The required equation (using any value of the y-intercept) is expressed as;

y = 5/7 x - 6

Note that the y-intercept value was assumed and any value can be used

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The areas of the figures are 4(x + 1), 7(d + 4) and y(y + 3)

<h3>How to determine the total areas?</h3>

<u>The figure 1</u>

In this figure, we have

Length = x + 1

Width = 4

The area is calculated as:

Area = Length * Width

So, we have

Area = 4(x + 1)

<u>The figure 2</u>

In this figure, we have

Length = d + 4

Width = 7

The area is calculated as:

Area = Length * Width

So, we have

Area = 7(d + 4)

<u>The figure 3</u>

In this figure, we have

Length = y + 3

Width = y

The area is calculated as:

Area = Length * Width

So, we have

Area = y(y + 3)

Hence, the areas of the figures are 4(x + 1), 7(d + 4) and y(y + 3)