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dybincka [34]
4 years ago
8

-0.111c + 1 = 0.889c

Mathematics
1 answer:
Elena-2011 [213]4 years ago
7 0

Answer:

-0.111c + 1 = 0.889c = c=1

Subtract 0.889c from both sides:

−0.111c+1−0.889c=0.889c−0.889c

−c+1=0

Subtract 1 from both sides.:

−c+1−1=0−1

−c=−1

Divide both sides by -1.:

-c/1 = -1/-1

Therefore, your answer is c=1

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Mars2501 [29]

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a)  1.59967 * 10 ^-12

b)    7.52711497

c)  1.590778098 * 10^-1

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b=4.61 x 10^-7,

c=5.52 x 10^-7

a)  a*b =  3.47 x 10^-6* 4.61 x 10^-7

We multiply the numbers out front and add the exponents

        (3.47*4.61) * 10^(-6+-7)

        15.9967 * 10^-13

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1.59967 * 10^(-13+1)

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b)   a/b = 3.47 x 10^-6/ 4.61 x 10^-7

We divide the numbers out front and subtract the exponents

        (3.47/4.61) * 10^(-6- -7)

         (3.47/4.61) * 10^(-6+7)

         .752711497* 10^1

But this is not correct scientific notation, we need 1 number in front of the decimal.  Move the decimal 1 place to the right and subtract 1 from the exponent

7.52711497* 10^1-1

7.52711497

c)  c/a = 5.52 x 10^-7/3.47 x 10^-6

We divide the numbers out front and subtract the exponents

        (5.52/3.47) * 10^(-7- -6)

        (5.52/3.47) * 10^(-7+6)

          1.590778098 * 10^-1

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3 years ago
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