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3 years ago

Which of the algebraic expressions are linear expressions? Select two answers.

Mathematics

1 answer:

cupoosta [38]3 years ago

8 0

Answer:

Option A and Option E

Step-by-step explanation:

By definition linear expressions have the following form:

$ax ^ n + b$

where

$n= 0$ or $n=1$

To answer the question, identify among the options the expressions that have this form:

Option A.

$-9y$

Where $a =-9$ and $b=0$ and $n=1$

Option E.

$-\frac{4}{5}x+\frac{3}{8}$

Where $a=-\frac{4}{5}$ and $b=\frac{4}{5}$ and $n=1$

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The equation of line q is 5y - 4x = 10. Write an equation of the line that is perpendicular to q and passes through the point (-

Hitman42 [59]

Y=mx+b
m=slope
b=y intercept

perpendicuar lines have slopes that multiply to get -1
so
solving for y
add 4x both sides and divide by5 to get
y=4/5x+2
slope is 4/5

perpendicular means the slopes multiply to get -1
so
4/5 times what=-1?
what=-5/4

so
y=(-5/4)x+b
find b
given the point (-15,8)
8=(-5/4)(-15)+b
8=75/4+b
-43/4=b

y=(-5/4)x-43/4

6 0

2 years ago

Read 2 more answers

this picture is a scale drawing of a basketball court and 1 inch on the picture represents 15 feet of actual length. the dementi

bekas [8.4K]

If one inch represents 15 feet, then:

2 inches represent:
2 * 15 = 30 feet

1 2/3 inches represent:
1 2/3 * 15 =
= 5/3 * 15 =
= 75/3 =
= 25 feet

So the real area of the court is 30 * 25 = 750 square feet.

5 0

3 years ago

The sum of a number and 12

bekas [8.4K]

Answer:

the sum of 6+6 is 12

Step-by-step explanation:

so the sum of the number 6+6 is 12 plz like and rate

5 0

3 years ago

Watch help

babymother [125]

Answer:

m∠RPQ = 8°

Step-by-step explanation:

m∠QRS = 4x - 15

m∠RPQ = x + 1

m∠PQR = x - 2

m∠QRS is exterior angle and m∠RPQ and m∠PQr are opposite interior angles to m∠QRS

m∠QRS = m∠RPQ + m∠PQR {Exterior angle property of triangle}

4x - 15 = x +1 + x - 2

4x - 15 = x + x + 1-2 {Combine like terms}

4x - 15 = 2x - 1 {Subtract 2x from both sides}

4x - 2x - 15 = - 1

2x - 15 = - 1 {Add 15 to both sides}

2x = -1 + 15

2x = 14 {Divide both sides by 2}

x = 14/2

x = 7

m∠RPQ = x + 1 = 7 + 1 = 8°

4 0

3 years ago

Read 2 more answers

Among persons donating blood to a clinic, 85% have Rh+ blood (that is, the Rhesus factor is present in their blood.) Six people

Leona [35]

Answer:

a) There is a 62.29% probability that at least one of the five does not have the Rh factor.

b) There is a 22.36% probability that at most four of the six have Rh+ blood.

c) There need to be at least 8 people to have the probability of obtaining blood from at least six Rh+ donors over 0.95.

Step-by-step explanation:

For each person donating blood, there are only two possible outcomes. Either they have Rh+ blood, or they do not. This means that we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$p = 0.85, n = 6$ .

a) fine the probability that at least one of the five does not have the Rh factor.

Either all six have the factor, or at least one of them do not. The sum of the probabilities of these events is decimal 1. So:

$P(X < 6) + P(X = 6) = 1$

$P(X < 6) = 1 - P(X = 6)$

In which:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 6) = C_{6,6}.(0.85)^{6}.(0.15)^{0} = 0.3771$

$P(X < 6) = 1 - P(X = 6) = 1 - 0.3771 = 0.6229$

There is a 62.29% probability that at least one of the five does not have the Rh factor.

b) find the probability that at most four of the six have Rh+ blood.

Either more than four have Rh+ blood, or at most four have. So

$P(X \leq 4) + P(X > 4) = 1$

$P(X \leq 4) = 1 - P(X > 4)$

In which

$P(X > 4) = P(X = 5) + P(X = 6)$

$P(X = 5) = C_{6,5}.(0.85)^{5}.(0.15)^{1} = 0.3993$

$P(X = 6) = C_{6,6}.(0.85)^{6}.(0.15)^{0} = 0.3771$

$P(X > 4) = P(X = 5) + P(X = 6) = 0.3993 + 0.3771 = 0.7764$

$P(X \leq 4) = 1 - P(X > 4) = 1 - 0.7764 = 0.2236$

There is a 22.36% probability that at most four of the six have Rh+ blood.

c) The clinic needs six Rh+ donors on a certain day. How many people must donate blood to have the probability of obtaining blood from at least six Rh+ donors over 0.95?

With 6 donors:

$P(X = 6) = C_{6,6}.(0.85)^{6}.(0.15)^{0} = 0.3771$

37.71% probability of obtaining blood from at least six Rh+ donors over 0.95.

With 7 donors:

$P(X = 6) = C_{7,6}.(0.85)^{6}.(0.15)^{1} = 0.3960$

0.3771 + 0.3960 = 0.7764 = 77.64% probability of obtaining blood from at least six Rh+ donors over 0.95.

With 8 donors

$P(X = 6) = C_{8,6}.(0.85)^{6}.(0.15)^{2} = 0.2376$

0.3771 + 0.3960 + 0.2376 = 1.01 = 101% probability of obtaining blood from at least six Rh+ donors over 0.95.

There need to be at least 8 people to have the probability of obtaining blood from at least six Rh+ donors over 0.95.

5 0

3 years ago