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ruslelena [56]
3 years ago
14

1*10^-4 + 4*10^4 what is the answer

Mathematics
1 answer:
Kobotan [32]3 years ago
5 0

Answer:

40000.0001

Step-by-step explanation:

You just multiply 1*10^-4 plus 4*10^4

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What is 4 3\7 + 6 1\5
Anna11 [10]

Answer:depends on how u want it in mixed for its 10 22/35

Step-by-step explanation:

If u want it in another form use m a t h w a y but together

7 0
3 years ago
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Urgently need help!!! I will mark the best answer as BRAINLIEST!!!!!
Lady bird [3.3K]

C. 16.4

Step-by-step explanation:

The formula to apply here is;

A=P(1+r/n) ^nt where

A=final amount

P=starting amount

r=rate of interest annually

n=number of compounding per year

t=time in years

Given ; P=$500, A=$750 , r=2.5%=0.025 , t=?,n=1

Substitute values;

A=P(1+r/n)^nt

$750=$500(1+0.025)^t

750=500(1.025)^t

750/500=(1.025)^t

1.5=(1.025)^t

log 1.5 =t log (1.025)

log 1.5/log 1.025 = t

16.4 =t

Learn More

Compound interest formula :brainly.com/question/12148233

Keywords : bank account, interest per year, value of account, years

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3 0
4 years ago
Solve two step equations 18=-1/2x-7
lana66690 [7]

Answer:

X=-50

Step-by-step explanation:

18=-1/2x-7

-1/2x=18+7...... this is first step

X=25/(-1/2)...... the 2nd step

X=-50

7 0
3 years ago
Help algebra 2 please
iogann1982 [59]

Step-by-step explanation:

your answer is 1 option

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3 years ago
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Sally needs 2/3 of a pound of potatoes. This is 1/3 of a pound more than 4/3 of the potatoes Sally has in her pantry
amid [387]

Lets assume, Sally has X pound of potatoes in her pantry.

So, 4/3 of the potatoes Sally has in her pantry = \frac{4}{3}X

Now, Sally needs 2/3 pound of potatoes and this 2/3 pound of potatoes is 1/3 pound more than that \frac{4}{3}X

So the representing equation will be:

\frac{2}{3} =  \frac{1}{3}+ \frac{4}{3}X

\frac{2}{3} - \frac{1}{3} = \frac{4}{3} X (subtracting \frac{1}{3} from both sides)

\frac{1}{3}= \frac{4}{3}X

1= 4X (multiplying both sides by 3)

X =\frac{1}{4}

So, Sally has \frac{1}{4} pound of potatoes in her pantry.

4 0
3 years ago
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