Answer:
Probability each player gets an ace, a $2 and a $3 = 0.0374
Step-by-step explanation:
The total number of ways to divide the card in triples among four players = 369600 ways
The total number of ways to share the cards such that no card is repeated in each triple = 13824 ways
Probability each player gets an ace, a $2 and a $3 = 13824/369600
Probability each player gets an ace a $2 and a $3 = 0.0374
Note: Further explanation is provided in the attachment.
Using the z-distribution, it is found that the 95% confidence interval is (0.46, 0.526), and it does not provide strong evidence against that belief.
<h3>What is a confidence interval of proportions?</h3>A confidence interval of proportions is given by:
In which:
In this problem, we have a 95% confidence level, hence, z is the value of Z that has a p-value of
, so the critical value is z = 1.96.
We have that a random sample of 864 births in a state included 426 boys, hence the parameters are given by:
Then, the bounds of the interval are given by:
The 95% confidence interval estimate of the proportion of boys in all births is (0.46, 0.526). Since the interval contains 0.506, it does not provide strong evidence against that belief.
More can be learned about the z-distribution at brainly.com/question/25890103