Answer:
•A c-chart is the appropriate control chart
• c' = 8.5
• Control limits, CL = 8.5
Lower control limits, LCL = 0
Upper control limits, UCL = 17.25
Step-by-step explanation:
A c chart is a quality control chart used for the number of flaws per unit.
Given:
Past inspection data:
Number of units= 100
Total flaws = 850
We now have:
c' = 850/100
= 8.5
Where CL = c' = 8.5
For control limits, we have:
CL = c'
UCL = c' + 3√c'
LCL = c' - 3√c'
The CL stands for the normal control limit, while the UCL and LCL are the upper and lower control limits respectively
Calculating the various control limits we have:
CL = c'
CL = 8.5
UCL = 8.5 + 3√8.5
= 17.25
LCL = 8.5 - 3√8.5
= -0.25
A negative LCL tend to be 0. Therefore,
LCL = 0
<span>If 3x-1=11, then 2x=?
</span><span>
2x + x - 1 = 11
2x = -x +12</span>
Answer:
(3,1)
Step-by-step explanation:
If you plot both of the points on a graph you get another straight line.
When you connect the dots you get 3,1 as the midpoint of the two segments :))
1.
In line with the test each person who came into interaction
with the infected person will become infected also. With this information, the
calculation would be: 9 people each day for 7days would be equivalent to 9 x 7
which equals 63 people.
2.
Here were 7 other people in the experiment if patient
zero is left out. If each person intermingled with 6 different people every day
in 7 days then the calculation would be: 7 people infected x 6 new people = 42
infected people each day
42 new people every day x 7 days = 294
infected persons.
Pretty sure the answer is C since the point is at 1 on the c-axis