C would be your answer and here is how you would solve the problem.
Let the angles be A and C
<span>Complimentary angles, therefor </span>
<span>A + C = 90 </span>
<span>The measurement of the complement of an angle exceeds the measure of the angle by 25% (you used a % sign so I'll use % instead of degrees) </span>
<span>C = 1.25A </span>
<span>Substitute </span>
<span>A + 1.25A = 90 </span>
<span>2.25A = 90 </span>
<span>A = 40º <----- </span>
<span>C = 50º <----- </span>
<span>------------------------------ </span>
<span>If you meant 25º </span>
<span>A + (A + 25) = 90 </span>
<span>2A + 25 = 90 </span>
<span>2A = 65 </span>
<span>A = 32.5º </span>
<span>C = 57.5º</span>
Hell naw, nobody is about to do that for you
F ( x ) = ( 3 x + 6 ) ( 3 x - 6 ) / ( 3 x + 6 ) = 3 x - 6
and for domain : 3 x + 6 ≠ 0
3 x ≠ - 6
x ≠ - 2
anwser graph of 3 x - 6, with discontinuity at - 2
I'll write the equation again with the blanks filled in.
1/2 of 2/3 = 1/2 of two thirds = one third
2/3 is read as two thirds.
Half of 2/3 is 1/3, because 1/3+1/3=2/3
Hope this helps!
