Step-by-step explanation:
the total cost is, of course, first the cost to buy the copier, and then the running costs per copy made.
it is really that easy.
the equations just put this into mathematical form :
A
y = 0.02×x + 800
B
y = 0.06×x + 600
please notice, we put $600 or $800 in as constant term, because these costs are the starting costs that we have, even if we never make a single copy (x = 0).
and then the total cost goes up with every copy we make.
I cannot draw here.
so, to find the number of copies where both copier systems would cost the same, means we have to say both equating deliver the same result :
0.02×x + 800 = 0.06×x + 600
200 = 0.04×x
x = 200 / 0.04 = 5000
when making 5000 copies both costs are the same.
The age of the Harry in the terms of variable <em>x, </em>as the age of his father is (x+4) is represent with following equation.

<h3>
How to write algebraic expression? </h3>
Algebraic expression are the expression which consist the variables, coefficients of variables and constants.
The algebraic expression are used represent the general problem in the mathematical way to solve them.
Harry is one third as old as his father and his father is x+12 years old.To find the age of Harry, we need to convert the given statement into the algebraic expression.
Suppose the age of the Harry is <em>a</em> years and the age of his father is<em> b</em> years. Now Harry is one third as old as his father, thus

Let the above equation is equation one.
As the father of Harry is x+12 years old. Thus put the value of age of his father in the equation one as,

The age of the Harry in the terms of variable <em>x, </em>as the age of his father is (x+4) is represent with following equation.


Learn more about the algebraic expression here;
brainly.com/question/2164351
Answer:
-3 is the answer
Step-by-step explanation:
distribute the value of n
3+4-5×2
=7-10
=-3
You add all the numbers & divide it by how many numbers 8 +9+9+9+10+10
<span>probability that the card is a red 8
=
2 out of 52 or 1 out of 26
hope it helps</span>