Answer: 387
Step-by-step explanation:
Given : Standard deviation: ![\sigma=2.3](https://tex.z-dn.net/?f=%5Csigma%3D2.3)
Margin of error : 0.15
Critical value for 80% confidence interval = 1.2816
Required minimum sample size : ![n=(\dfrac{z_{\alpha/2}\cdot \sigma}{E})^2](https://tex.z-dn.net/?f=n%3D%28%5Cdfrac%7Bz_%7B%5Calpha%2F2%7D%5Ccdot%20%5Csigma%7D%7BE%7D%29%5E2)
![\\\\=(\dfrac{1.2816\times2.3}{0.15})^2\\\\=386.16966144\approx387](https://tex.z-dn.net/?f=%5C%5C%5C%5C%3D%28%5Cdfrac%7B1.2816%5Ctimes2.3%7D%7B0.15%7D%29%5E2%5C%5C%5C%5C%3D386.16966144%5Capprox387)
Hence, the minimum sample size required to estimate the mean usage of water = 387
It would take 428 seconds to swim 500 yards
I have to the answer is 25 I believe have a very nice day
First one (x,y)=(0,-25/2) Second one (x,y)=(0,-26/3
The answer is A because in the dotted line it corresponds to “y -3x-3”. You rise 3 and run only 1. The dotted line is going to the left because it’s a negative 3. The “y 1/3x-3” is the rise of 1 and the run of 3. Then place 0 into the x and y. Then once you place the 0 into both problems and if the problem is true then shade where the point 0,0 is. Since this problem is not true when placing 0 into the equation then you don’t shade where 0,0 is. Hopefully I explained this correctly.