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DerKrebs [107]
3 years ago
11

Lucero wants to hang 3 paintings in her room. The widths of the paintings are 10 1/2 inches, 3 1/2 feet, 2 feet, and 2 3/4 inche

s. If she hangs them next to each other with 3 inches between them, what is the total width of the wall space she will need?
Mathematics
1 answer:
Marina86 [1]3 years ago
8 0

Answer:

  7 ft 1 1/4 in

Step-by-step explanation:

The total width of 3 paintings and 2 spaces is ...

  (10.5 in) + (3 in) + (3 ft 6 in) + (3 in) + (2 ft 2 3/4 in)

  = (10.5 +3 +6 +3 +2.75) in + (3 +2) ft

  = 25.25 in + 5 ft = 1.25 in + 24 in + 5 ft

  = 7 ft 1 1/4 in

The total width of wall space needed for the paintings is 7 feet 1 1/4 inches.

_____

If two more 3-inch spaces are added, one on each end, then the total width is 7 feet 7 1/4 inches. The problem isn't clear about that, saying only that there are spaces between the paintings.

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A sweet factory produces 5 different chocolate bars. the different flavors are always produced in the same proportions, for ever
IRISSAK [1]

a. There are 933 chocolate bars

b. There are 1200 chocolate bars

c. There are 1580 chocolate bars

<h3>How to calculate the number of chocolate bars</h3>

Since there are 5 different flavors,

let

  • x = orange flavored bars,
  • y = coconut flavored bars,
  • z = coffee flavored bars,
  • a = strawberry flavored bars and
  • b = honeycomb flavored bars and
  • X = total number of bars

Since the different flavors are always produced in the same proportions, for every 4 coconut flavored bars 5 honeycomb 6 orange 1 coffee and 4 strawberry

So, the ratio of their proportions are x:y:z:a:b = 6:4:2:1:5

So, the total ratio is T = 6 + 4 + 1 + 4 + 5 = 20

<h3>a. What is the total number of chocolate bars if there are 280 orange flavored bars?</h3>

Since we have 6 orange flavored bars, the ratio of orange flavored bars to total is 6/20

So, the amount of orange flavored bars is x = 6/20 × X

Making X subject of the formula, we have

X = 20x/6

So, if there are 280 orange bars, there will be

X = 20x/6

X = 20 × 280/6

X = 5600/6

X = 933.33

X ≅ 933 chocolate bars

So, there are 933 chocolate bars

<h3>b. What is the total number of chocolate bars if there are 960 coconut flavored bars?</h3>

Since we have 4 coconut flavored bars, the ratio of coconut flavored bars to total is 4/20

So, the amount of coconut flavored bars is y = 4/20 × X

Making X subject of the formula, we have

X = 20y/4

So, if there are 960 coconut flavored bars, there will be

X = 20y/6

X = 20 × 960/4

X = 5 × 240

X = 1200 chocolate bars

So, there are 1200 chocolate bars

<h3>c. What is the total number of chocolate bars if there are 79 coffee flavored bars?</h3>

Since we have 1 coffee flavored bars, the ratio of coffee flavored bars to total is 1/20

So, the amount of coconut flavored bars is z = 1/20 × X

Making X subject of the formula, we have

X = 20z

So, if there are 79 coffee flavored bars, there will be

X = 20z

X = 20 × 79

X = 1580 chocolate bars

So, there are 1580 chocolate bars

Learn more about ratio here:

brainly.com/question/1127546

#SPJ1

7 0
1 year ago
Matt invests $1,669 in a saving account with a fixed annual interest rate of 2% compounded 12 times per year. How long will it t
vesna_86 [32]

Answer:

It will take 4.84 years

Step-by-step explanation:

The initial amount that Matt invested was $1669. It means that principal is

P = 1669

It was compounded 12 times per year. So

n = 12

The rate at which the principal was compounded is 2%. So

r = 2/100 = 0.02

The formula for compound interest is

A = P(1+r/n)^nt

A = total amount in the account at the end of t years.

A = 1,844.38

Therefore

1,844.38 = 1669(1+0.02/12)^(12×t)

1,844.38/1669 = (1.0017)^(12t)

1.1051 = (1.0017)^(12t)

Taking log to base 10 of both sides, it becomes

Log 1.1051 = log 1.0017^(12t)

Log 1.1051 = 12tlog 1.0017

0.043 = 0.00074 × 12t

0.043 = 0.00888t

t = 0.043/0.00888

t = 4.84 years

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Consider the following data set:
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Answer:

+5 Range; The range is now 25

Step-by-step explanation:

The original range would be calculated by subtracting 20 from 40, giving you 20 as the range. However, with the point 15 added, there would be a new lowest number, making the new range be 40-15, which is 25.

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The table shown below shows some values for functions f(x) and g(x). What is/are the solutions for f(x) =g(x)
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i need this answer too

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How do I solve this problem
CaHeK987 [17]
Use cymath it gives you the answer :)
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