Answer:
(0 , -1)
Step-by-step explanation:
WR = 4 + 2 = 6
WS = 1/3 x WR = 2 .... the point of 1:2 of WR
S (-2 + 2 , -4) i.e. (0,4)
The same reason: RQ = 1/3 x RY = 1/3 x (5 + 4) = 3
Q (-4 , -4 + 3) i.e. (-4, -1)
QP // RW
p (0 , -1)
Answer:
A = 177.46
Step-by-step explanation:
A = 6*6+6root((6/2)^2+11.4^2)+6root((6/2)^2+11.4^2)
A = 177.46
Answer:
The second time when Luiza reaches a height of 1.2 m = 2 08 s
Step-by-step explanation:
Complete Question
Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts jumping. Here, the angle is entered in radians.
H(t) = -0.6 cos (2pi/2.5)t + 1.5.
What is the second time when Luiza reaches a height of 1.2 m? Round your final answer to the nearest hundredth of a second.
Solution
Luiza is jumping on trampolines and her height above the levelled ground at any time, t, is given as
H(t) = -0.6cos(2π/2.5)t + 1.5
What is t when H = 1.2 m
1.2 = -0.6cos(2π/2.5)t + 1.5
0.6cos(2π/2.5)t = 1.2 - 1.5 = -0.3
Cos (2π/2.5)t = (0.3/0.6) = 0.5
Note that in radians,
Cos (π/3) = 0.5
This is the first time, the second time that cos θ = 0.5 is in the fourth quadrant,
Cos (5π/3) = 0.5
So,
Cos (2π/2.5)t = Cos (5π/3)
(2π/2.5)t = (5π/3)
(2/2.5) × t = (5/3)
t = (5/3) × (2.5/2) = 2.0833333 = 2.08 s to the neareast hundredth of a second.
Hope this Helps!!!
95
Step-by-step explanation:
she would have to get At Least 95 or better to balance it out
Answer:
y+1=5/2(x+2)
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(-6-(-1))/(-4-(-2))
m=(-6+1)/(-4+2)
m=-5/-2
m=5/2
y-y1=m(x-x1)
y-(-1)=5/2(x-(-2))
y+1=5/2(x+2)
