Find the area of the following trapezoid.
2 answers:
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Answer:
Step-by-step explanation:
First thing I would do is square the 14, and put it under the radical. Itll make the calculations a little bit easier.
14sqrt(2) = sqrt392
Use the definition of sine to find the value of a
sin(45) = opposite/hypotenuse = a/sqrt392
a = 14
Answer:
CN = 7
Step-by-step explanation:
In the attached figure, we have drawn line CD parallel to AB with D a point on line MK. We know ΔMNT ~ ΔDCT by AA similarity, and because of the given angle congruence, both are isosceles with CD = CT. Likewise, we know ΔCDK is congruent to ΔBMK by AAS congruence, since BK = CK (given).
Then CD = BM (CPCTC). Drawing line NE creates isosceles ΔNEC ~ ΔTDC and makes CE = AB. Because ΔNEC is isosceles, CN = CE = AB = 7.
The length of segment CN is 7.
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If you assume CN is constant, regardless of the location of point N (which it is), then you can locate point N at B. That also collocates points T and K and makes ΔBMK both isosceles and similar to ΔBAC. Then CN=AB=7.
