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fenix001 [56]
4 years ago
14

Find the distance between the pair of points (2,6) and (7,-4)​

Mathematics
1 answer:
ICE Princess25 [194]4 years ago
3 0
The distance will be 11.1803.
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The shear strength of each of ten test spot welds is determined, yielding the following data (psi).
Mumz [18]

Answer:

a) Mean = 382.3 psi

Standard deviation = 20.8 psi

b) 392.7 psi

c) P(X<400)=0.8026

Step-by-step explanation:

a) The population mean can be estimated as equal to the mean of the sample, and the population standard deviation can be estimated from the sample standard deviation:

M=\frac{1}{n}\sum x_i=\frac{1}{10}(389+405+409+367+358+415+376+375+367+362)\\\\M=\frac{1}{10}(3823)=382.3\\\\\mu\approx M=382.3

s=\sqrt{\frac{1}{n-1}\sum (x_i-M)^2}=\sqrt{\frac{1}{10-1}(389-382.3)^2+...+(362-383.2)^2}\\\\\\s=\sqrt{\frac{1}{9}(3906.1)}=\sqrt{434}=20.8\\\\\\\sigma\approx s=20.8

b) We start by searching for the z-value for the 95th percentile. This value is

z=1.645:

P(z

Then, the strength value below which 95% of all welds will have their strengths is:

X=\mu+z\cdot \sigma/\sqrt{n}=382.3+1.645*20.8/\sqrt{10}\\\\X=382.3+32.9/3.2=382.3+10.4\\\\X=392.7

c) We calculate the probability of X being equal or less than 400 as:

z=(X-\mu)/\sigma=(400-382.3)/20.8=17.7/20.8=0.851\\\\\\P(X\leq400)=P(z

6 0
3 years ago
Can someone please help me with this question?!
RideAnS [48]
It is c the answer of it
6 0
3 years ago
The function below represents the cost C (in dollars) of renting a car after driving m miles. What would the cost be to rent the
kumpel [21]

Answer:

Hello! Unfortunately we cannot answer the question due to the fact that we don't have the picture. Make sure you save the picture and upload it to your question.

Step-by-step explanation:

5 0
3 years ago
Help need answers asap
Rasek [7]

Answer:

x = 25

y = 6

Step-by-step explanation:

< B = < M

2x - 20 = 30

2x = 50

<u>x = 25</u>

AB = LM

7y - 8 = 2y + 22

5y = 30

<u>y = 6</u>

7 0
3 years ago
Mrs. R is pregnant and very worried that the child will have beta-thalassemia. What is the probability that the child will have
kenny6666 [7]

Answer:

There are three kind of beta-thalassemia.

Total possible outcome=  3 types of beta- thalassemia + 1 [child will have no trace of disease] = 4

As we know Probability(outcome) = \frac{\text{ Total favorable outcome}}\text{Total possible outcome}

Probability that the child will have beta-thalassemia major =\frac{_{1}^{3}\textrm{C}}{_{1}^{4}\textrm{C}}

     =\frac{3}{4}

   ∴ favorable=_{1}^{3}\textrm{C}

 And , Total =_{1}^{4}\textrm{C}

Probability that the child will have no trace of the disease=\frac{1}{4}





4 0
4 years ago
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