Question

. One jar contains 43 grape Skittles, 23 orange, 15 yellow, 18 cherry, and 12 lime. Another jar contains 20 grape, 22 orange, 18 yellow, 21 cherry and 19 lime. You close your eyes and grab one Skittle from each jar. What is the probability both are grape? What is the probability neither are grape?

Answer 1

Answer:

see below

Step-by-step explanation:

Jar 1 :

43 grape Skittles, 23 orange, 15 yellow, 18 cherry, and 12 lime = 111

P ( grape ) = 43/111

Jar 2 :

20 grape, 22 orange, 18 yellow, 21 cherry and 19 lime = 100

P ( grape ) = 20/100 = 1/5

P(grape, grape ) = 43/111 *1/5 = 43/555

Jar 1 :

43 grape Skittles, 23 orange, 15 yellow, 18 cherry, and 12 lime = 111

P ( not grape grape ) =68/111

Jar 2 :

20 grape, 22 orange, 18 yellow, 21 cherry and 19 lime = 100

P ( grape ) = 80/100 = 4/5

P(grape, grape ) =68/111 *4/5 =272/555